A company's records show that 35% of the employees receive a performance bonus. T randomly selects a sample of 5 employees from the company. 11. The probability that none of these employees receive a performance bonus is: A 0.247 В 0.186 C 0.884 0.116 12. The probability that at most 2 of these employees receive a performance bonus is: A 0.678 В 0.808 C 0.706 0.765

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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A company's records show that 35% of the employees receive a performance bonus. I
randomly selects a sample of 5 employees from the company.
11. The probability that none of these employees receive a performance bonus is:
A
0.247
В
0.186
C
0.884
0.116
12. The probability that at most 2 of these employees receive a performance bonus is:
А
0.678
B
0.808
C
0.706
D
0.765
13. Consider the normal distribution function. The area between z -scores of – 1.56 i
A
0.9105
В
0.0293
C
0.856
D
0.9398
Transcribed Image Text:A company's records show that 35% of the employees receive a performance bonus. I randomly selects a sample of 5 employees from the company. 11. The probability that none of these employees receive a performance bonus is: A 0.247 В 0.186 C 0.884 0.116 12. The probability that at most 2 of these employees receive a performance bonus is: А 0.678 B 0.808 C 0.706 D 0.765 13. Consider the normal distribution function. The area between z -scores of – 1.56 i A 0.9105 В 0.0293 C 0.856 D 0.9398
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