A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 250.9-cm and a standard deviation of 1-cm. For shipment, 27 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 251.1-cm. P(M > 251.1-cm) =
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A company produces steel rods. The lengths of the steel rods are
Find the probability that the average length of a randomly selected bundle of steel rods is greater than 251.1-cm.
P(M > 251.1-cm) =
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- A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 203.7-cm and a standard deviation of 2.5-cm. For shipment, 28 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is between 202.9-cm and 204.3-cm.PP(202.9-cm < ¯xx¯ < 204.3-cm) = Enter your answer as a number accurate to 4 decimal places.A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 240-cm and a standard deviation of 1.4-cm. For shipment, 30 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is less than 240.6-cm.P(M < 240.6-cm) =A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 99.3-cm and a standard deviation of 1.5-cm. For shipment, 25 steel rods are bundled together.Find P27, which is the average length separating the smallest 27% bundles from the largest 73% bundles. P27 =
- A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 217.3-cm and a standard deviation of 2.3-cm. For shipment, 15 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 216.2. cm and 218.9-cm. P(216.2-cm < M 218.9-cm) - Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z- scores rounded to 3 decimal places are accepted. Submit Question 4A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 225.1-cm and a standard deviation of 1.4-cm. For shipment, 12 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is between 224.1-cm and 224.6-cm. P(224.1-cm < M < 224.6-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.A particular fruit's weights are normally distributed, with a mean of 455 grams and a standard deviation of 31 grams. If you pick 19 fruit at random, what is the probability that their mean weight will be between 434 grams and 443 grams? Use GeoGebra. Round to 4 places.
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- A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 157-cm and a standard deviation of 0.9-cm. For shipment, 5 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 156-cm and 157.2-cm.P(156-cm < M < 157.2-cm)A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 119.5-cm and a standard deviation of 2.2-cm. For shipment, 24 steel rods are bundled together.Find P75, which is the average length separating the smallest 75% bundles from the largest 25% bundles.P75 = -cmA company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 122.7-cm and a standard deviation of 0.5-cm.Find P15, which is the length separating the shortest 15% rods from the longest 85%.P15 = -cm