A company is doing a hypothesis test on the variation of quality from two suppliers. Both distributions are normal, and the populations are independent. use a = 0.01 Ho :012 = 0 2 2 На : 01 2 O 2 The standard deviation of the first sample is 2.3235 with a sample size of 28 4.2411 is the standard deviation of the second sample with a sample size of 13. The test statistic (rounded to 3 decimal places) is = O Fail to reject the null hypothesis O Reject the null hypothesis
Q: An agricultural company is trying to decide which type of fertilizer to use on its crops. The…
A: It is assumed that the population standard deviations (σ1 and σ2) are not equal.
Q: Some manufacturers claim that non-hybrid sedan cars have a lower mean miles-per-gallon (mpg) than…
A: As, let the population 1 denote non - hybrids and population 2 denotes hybrids, the answer for test…
Q: An agricultural company is trying to decide which type of fertilizer to use on its crops. The…
A: Given information- For fertilizer A- Sample size n1 = 41 Sample mean, x1 = 183 tons Sample standard…
Q: A psychologist wants to test whether there is any difference in puzzle-solving abilities between…
A:
Q: Apple claims that the iPad has very good battery life. Albert collected a simple random sample of 30…
A: Given n=30
Q: Human heights are one of many biological random variables that can be modeled by the normal…
A: Given that Mean=M=176.7 Standard deviation=S=9.9
Q: The average income among a sample of 75 students studying at University of Chichester is found to be…
A: sample size(n)=75Mean()=50standard deviation(s)=13confidence interval=95%
Q: A coin-operated drink machine was designed to discharge a mean of 9 fluid ounces of coffee per cup.…
A: GivenMean(x)=9.03standard deviation(s)=0.23sample size(n)=17α=0.10
Q: Suppose that you take a random sample of 30 healthy American men... What is the z-score…
A: The mean is 82 and the standard deviation is 10.
Q: An agricultural company is trying to decide which type of fertilizer to use on its crops. The…
A: We have to fínd conclusion.
Q: In a recent year, 11th grade New York public school students taking an English test produced test…
A:
Q: Scores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes…
A: We have given that The mean 107, sample standard deviation 23, sample size 55 and significance…
Q: Find the lower boundary of the 90% confidence interval for the variance of the ages of seniors at…
A: Given information: n=24 s=2.04 Confidence interval for variance: n-1s2χ1-α2,n-12≤σ2≤n-1s2χα2,n-12
Q: Scores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes…
A: Here in this problem the null hypothesis is the mean of IQ scores is less than 110 and the…
Q: The manager of a computer retails store is concerned that his suppliers have been giving him laptop…
A:
Q: he results of a statistics examination follow an approximately normal distribution with a mean of 68…
A: Given data,Mean μ=68Variance σ2=64sd σ=8P(X>82)=?
Q: Assume thAt scores on a standardized test are known to follow a bell shaped distribution with a mean…
A: L
Q: Some manufacturers claim that non-hybrid sedan cars have a lower mean miles-per-gallon (mpg) than…
A: Given that, Some manufacturers claim that non-hybrid sedan cars have a lower mean miles-per-gallon…
Q: A study of snow in Wyoming has a mean thickness of 68cm. A random sample of 12 snow piles in…
A: From the given information, the claim of the problem is the mean thickness of snow in Washington is…
Q: Response to allergen inhalation in allergic primates. In a study of 12 monkeys, the standard error…
A: From the provided information, Sample size (n) = 12 Standard error (SE) = 0.4
Q: A random sample of daily high temperatures in January and February are listed. At an alpha equal to…
A: The objective of this question is to determine if there is a significant difference in the variances…
Q: A coin-operated drink machine was designed to discharge a mean of 6 fluid ounces of coffee per cup.…
A: Given,sample size(n)=19sample mean(x¯)=5.89standard deviation(s)=0.2α=0.10
Q: An agricultural company is trying to decide which type of fertilizer to use on its crops. The…
A: Formula : Test statistic
Q: A psychologist reports that the average length of R.E.M. sleep in his test subjects was 10 minutes.…
A: Hypothesis Testing: Hypothesis is a procedure by which we can tests an assumption regarding a…
Q: The mean throwing distance of a football for Marco, a high school freshman quarterback, is 40 yards,…
A: According to policy we answer 3 part kindly repost for remaining.
Q: A sample of final exam scores is normally distributed with a mean equal to 20 and a variance equal…
A:
Q: An agricultural company is trying to decide which type of fertilizer to use on its crops. The…
A: We have to find hypothesis..
Q: A standardized test is given to a sixth grade class. Historically the mean score has been 143 with a…
A: Suppose σ is the population standard deviation of the performance scores.
Q: Student one claims that his grades this semester are higher than student two. They decide to test…
A: Given information : Student 1 : The number of classes for student 1 is The average grade is:…
Q: Inexpensive bathroom scales are not consistently accurate. A manufacturer of bathroom 150-pound…
A: Given population mean = 150 population standard deviation =2
Q: An agricultural company is trying to decide which type of fertilizer to use on its crops. The…
A: Given: for fertilizer A n1=41 meanx1=183 standard deviation(S1)=37 for fertilizer B n2=61…
Q: When calculating an ANOVA, if the research hypothesis is in fact true, then. variance due to group…
A:
Q: Does the data from the sample support his claim at a significance level of 0.05?
A: It is given that Sample size n = 60 Sample mean M = 3012 Sample SD s = 112 Level of significance =…
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Given data,n1=40x1=46.6σ1=4.6n2=45x2=48.8σ2=2.4Compute value of test statistic?
Q: Assume that the mean weight for American men in their twenties is 180 pounds with a standard…
A: The provided sample mean is Xˉ=175\bar X = 175 and the known population standard deviation is…
Q: A coin-operated drink machine was designed to discharge a mean of 7 fluid ounces of coffee per…
A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts. In case…
Q: An instructor has two different copies of a test, and randomly distributes them to their students.…
A: Introduction: Denote μ1, μ2 as the true population mean scores for test versions B and C…
Q: f the value of adult male cholesterol is a normal distribution with a mean of 198 and a standard…
A: The question is about normal dist. Given : Mean of cholesterol value of adult male ( μ ) = 198 Std.…
Q: The manager of a computer retails store is concerned that his suppliers have been giving him laptop…
A: Solution: Let X be the replace times for the model laptop of concern. From the given information, X…
Q: Suppose a random sample of adult women has a sample mean height of x¯=64.3 inches, with a sample…
A: From the Empirical rule, we know that 99.7% fall within three standard deviations from the mean.…
Q: An agricultural company is trying to decide which type of fertilizer to use on its crops. The…
A:
Q: A professor has two Engineering Mathematics classes, X and Y. Class X has 13 students and class Y…
A:
Q: Scores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes…
A:
Q: Scores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes…
A: So we have population mean μ=190 and the researcher claim is that the average IQ score for students…
Q: Scores on a certain “IQ" test for 18-25 year olds are normally distributed. A researcher believes…
A: Given We have given p-value = 0.337 and level of significance α=0.05
Step by step
Solved in 2 steps with 2 images
- An ecologist is studying the impact of local polluted waters on the growth of alligators. The length of adult male alligators typically follows a normal distribution with a standard deviation of 2 feet. The ecologist wants to estimate the mean length of this population of alligators. Suppose she samples n alligators at random and uses the sample mean, X to as an estimator for u. a. What is the bias and variance of the estimator? (Note, these may be a function of n.) b. If n = 4, what is the probability that the estimator is within one foot of the true mean? (I.e. find P(|X – µ| < 1). c. What sample size, n, is required for the estimator to be within one foot of the true mean with 95% probability? (I.e. find the value of n that satisfies P(|X – µ| < 1) = 0.95.) d. Suppose the ecologist ends up sampling n = 9 alligators and calculates a sample mean of ī = 10.4 feet. Construct a 95% confidence interval for the population mean. e. Give an interpretation for the interval obtained in (d).Hurricane damage: In August and September 2005, Hurricanes Katrina and Rita caused extraordinary flooding in New Orleans, Louisiana. Many homes were severely damaged or destroyed, and of those that survived, many required extensive cleaning. It was thought that cleaning of flood-damaged homes might present a health hazard due to the large amounts of mold present in many of the homes. In a sample of 364 residents of Orleans Parish who had participated in cleaning of one or more homes, 72 had experienced symptoms of wheezing, and in a sample of 184 residents who had not participated in cleaning, 23 reported wheezing symptoms (numbers read from a graph). Can you conclude that the proportion of residents with wheezing symptoms is greater among those who participated in the cleaning of flood-damaged homes? Let p, denote the proportion of residents with wheezing symptoms who had cleaned flood-damaged homes, and let p, be the population proportion with wheezing symptoms who did not…An agricultural company is trying to decide which type of fertilizer to use on its crops. The company concerned with the average yield on its crops as well as the variance of their yields. In a sample of 41 different fields with using fertilizer A, the average crop yield per acre is 185 tons with a standard deviation of 35 tons. In a separate sample of 61 different fields using fertilizer B, the average crop yield is 175 tons with a standard deviation of 28 tons. When testing the hypothesis (at the 1% level of significance) that there is no difference between the average yields using the different fertilizers, what is the null and alternative hypotheses?
- A psychologist wants to test whether there is any difference in puzzle-solving abilities between boys and girls. Independent samples of eleven boys and seven girls were chosen at random. The boys took a mean of 37 minutes to solve a certain puzzle, with a standard deviation of 4.8 minutes. The girls took a mean of 35 minutes to solve the same puzzle, with a standard deviation of 4.5 minutes. Assume that the two populations of completion times are normally distributed, and that the population variances are equal. Can we conclude, at the 0.10 level of significance, that the mean puzzle-solving times for boys, μ1 is greater than the mean puzzle-solving times for girls, μ2? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. a. State the null hypothesis H0 and the alternative hypothesis H1. b. Find the value of the test statistic. (Round to three or more decimal…An agricultural company is trying to decide which type of fertilizer to use on its crops. The company concerned with the average yield on its crops as well as the variance of their yields. In a sample of 41 different fields with using fertilizer A, the average crop yield per acre is 185 tons with a standard deviation of 35 tons. In a separate sample of 61 different fields using fertilizer B, the average crop yield is 175 tons with a standard deviation of 28 tons. When testing the hypothesis (at the 5% level of significance) that the variance of one of these yields is significantly larger than the other, what is the null and alternative hypotheses?Scores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes that the average IQ score for students at a certain NJ college is less than 110 points, and so wants to test this hypothesis. The researcher obtain a SRS of 45 student IQ scores from school records and found the mean of the 45 results was 108 with a sample standard deviation of 21. The level of significance (alpha) used for this problem is 0.05. What is the appropriate test statistic (Student must complete by showing by formula using the ap- propriate values in that formula "showing work" and the final answer and appropriate label)? O T test score = (108-110)/(21/sqrt(45)) = -.639 T test score (108-110)/(21/sqrt(45)) = .639 %3D OT test score = (110-108)/(21/sqrt(45)) = .639 %3D T test score (108-110)/(45/sqrt(21)) =-.2037 %3D 素
- The environmental research scientists report that the exhaust emissions for a certain car model has a normal distribution with a mean of 1.45 grams of nitrous oxide per mile and a standard deviation of 0.4. The car manufacturer claims their new process reduces the mean level of exhaust emitted for this car model. A Simple random sample of 36 cars is taken and the mean level of exhaust emitted for this sample is 1.21 grams. (a) State the null and alternative hypotheses. (b) Calculate the test statistic. (c) Calculate the Zc and p-value. Draw the picture. (d) What is the decision at the 0.05 significance level?Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.The mean number of English courses taken in a two-year time period by male and female college students is believed to be about the same. An experiment is conducted and data are collected from 29 males and 16 females. The males took an average of three English courses with a standard deviation of 0.8. The females took an average of four English courses with a standard deviation of 1.0. Are the means statistically the same? (Assume a 5% level of significance.)
- Plzz solved both question (i and ii) Compulsoury... And explainThe time married men with children spend on child care averages 6.4hours per week (Time, March 12, 2012). You belong to a professionalgroup on family practices that would like to do its own study todetermine if the time married men in your area spend on child care per week differs from the reported mean of 6.4 hours per week. A sample of40 married couples will be used with the data collected showing thehours per week the husband spends on child care. The sample data arecontained in the file ChildCare. a. What are the hypotheses if your group would like to determine ifthe population mean number of hours married men are spendingin child care differs from the mean reported by Time in your area?b. What is the sample mean and the p-value?c. Select your own level of significance. What is your conclusion?Scores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes that the average IQ score for students at a certain NJ college is less than 110 points, and so wants to test this hypothesis. The researcher obtain a SRS of 45 student IQ scores from school records and found the mean of the 45 results was 108 with a sample standard deviation of 21. The level of significance (alpha) used for this problem is 0.05/ What is the appropriate test statistic (Student must complete by showing by formula using the ap- propriate values in that formula "showing work" and the final answer and appropriate label)? O T test score = (108-110)/(45/sqrt(21)) = -.2037 O I test score = (108-110)/(21/sqrt(45)) = -.639 T test score = (108-110)/(21/sqrt(45)) = .639 I test score = (110-108)/(21/sqrt(45)) = .639