A company is considering three pieces of equipment. Equipment A has a first cost of $80,000, AOC of $20,000, and a salvage value of $19,000 after 3 years. Equipment B will cost $210,000 with an AOC of $35,000 and a salvage of $40,000 after 9 years, and Equipment C has the first cost of $150,000 with an AOC of $28,000 and a salvage value of 30,000 after 6 years. Which equipment should the company select at an interest rate of 10% per year?
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D1.
![A company is considering three pieces of equipment. Equipment A has a first cost of $80,000,
AOC of $20,000, and a salvage value of $19,000 after 3 years. Equipment B will cost $210,000
with an AOC of $35,000 and a salvage of $40,000 after 9 years, and Equipment C has the first
cost of $150,000 with an AOC of $28,000 and a salvage value of 30,000 after 6 years.
Which equipment should the company select at an interest rate of 10% per year?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F64b640cf-b7c5-4c1c-ad5e-cf2092511e50%2F9d1b24da-9a92-43f7-be62-e020ec11dbce%2Fxmeana_processed.jpeg&w=3840&q=75)
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- A company is considering three pieces of equipment. Equipment A has a first cost of $80,000, AOC of $20,000, and a salvage value of $19,000 after 3 years. Equipment B will cost $210,000 with an AOC of $35,000 and a salvage of $40,000 after 9 years, and Equipment C has the first cost of S150,000 with an AOC of $28,000 and a salvage value of 30,000 after 6 years Which equipment should the company select at an interest rate of 10% per year?Two methods can be used to produce expansion anchors. Method A costs $ 70, 000 initially and will have a $15,000 salvage value after 3 years. The operating cost with this method will be $36,000 in year 1, increasing by $3200 each year. Method B will have a first cost of $ 116,000, an operating cost of $10000 in year 1, increasing by $10000 each year, and a $46, 000 salvage value after its 3 year life. At an interest rate of 8% per year, which method should be used on the basis of a present worth analysis?Trailer Treasures Inc. is considering two projects and must do one of them. Project A requires an investment of $35,000. Estimated annual receipts for 5 years are $14,000; estimated annual costs are $4,500. Alternatively, Project B requires an investment of $70,000 has annual receipts for 5 years of $20,000, and has annual costs of $4,500. Assume both proejcts have $10,000 salvage value and that MARR IS 15%/year. 1. What is the annual worth of Project A? 2. What is the annual worth of Project B? 3. Which project should be recommended? Why? Please show work through excel
- Two methods can be used to produce expansion anchors. Method A costs $70,000 initially and will have a $11,000 salvage value after 3 years. The operating cost with this method will be $22,000 in year 1, increasing by $2600 each year. Method B will have a first cost of $123,000, an operating cost of $8000 in year 1, increasing by $6500 each year, and a $33,000 salvage value after its 3-year life. At an interest rate of 15% per year, which method should be used on the basis of a present worth analysis? The present worth for method A is $ The present worth for method B is $[ Method (Click to select) is used to produce expansion anchors.Company A is considering two alternatives. Machine A has a first cost of $15,000. The life is 6 years and it has an annual maintenance and operating cost of $1,500. Machine B has a first cost of $18,000, a life of 8 years and a salvage value of $1,500. The annual operating cost is $1,000. Which machine should be used to justify the purchase of such machine if money is worth 7% and calculate the difference between the equivalent annual worths.Two techniques can be used to produce expansion anchors. Technique A costs $90,000 initially and will have a $12,000 salvage value after 3 years. The operating cost with this method will be $33,000 in year 1, increasing by $2600 each year. Technique B will have a first cost of $113,000, an operating cost of $7000 in year 1, increasing by $7000 each year,and a $43,000 salvage value after its 3-year life. At an interest rate of 13% per year, which technique should be used on the basis of a present worth analysis? Notice that there are no revenues. Please work out and do not use excel, however if you use excel please show how to input everything needed down to the formula, thank you!
- Two different types of hydraulic equipment are being considered for a certain power plant. Machine A has a first cost of P15,000, and a salvage value of P1,500, life is 6 years and has an annual maintenance an operating cost of P900. Machine B has a first cost of P18,000, life of 8 years with no salvage value. Annual operating cost is P750. Which machine would be used to justify the purchase of such machine if money is worth 7% and compute the difference between its equivalent present worth? Show solutions.Two methods can be used to produce expansion anchors. Method A costs $80,000 initially and will have a $15,000 salvage value after 3 years. The operating cost with this method will be $30,000 in year 1, increasing by $4000 each year. Method B will have a first cost of $120,000, an operating cost of $8000 in year 1, increasing by $6500 each year, and a $40,000 salvage value after its 3-year life. At an interest rate of 12% per year, which method should be used on the basis of a present worth analysis?One of two methods will produce solar panels for electric power generation. Method 1 will have an initial cost of $550,000, an annual operating cost of $160,000 per year, and a $125,000 salvage value after its three-year life. Method 2 will cost $830,000 with an annual operating cost of $120,000, and a $240,000 salvage value after its five-year life. The company has asked you to determine which method is economically better, but it wants the analysis done over a three-year planning period. The salvage value of Method 2 will be 35% higher after 3 years than it is after 5 years. If the company’s MARR is 10% per year, which method should the company select?
- Two stamping machines are under consideration for purchase by a metal recycling company. The manual model will cost $25,000 to buy with an eight-year life and a $5,000 salvage value. Its annual operating costs will be $16,000. A computer-controlled model will cost $95,000 to buy and it will have a twelve-year life if upgraded at the end of year six for $15,000. Its terminal salvage value will be $23,000, with annual operating costs of $7,500 for labor and $2,500 for maintenance. The company's minimum attractive rate of return is 18%.Two different mutually exclusive alternatives can be used for producing a certain machine part. Alternative A will have a first cost of $60,000 with a $15,000 salvage value after its 3 year life. The operating cost with this method will be $35,000 per year. Alternative B will cost $45,000, but it will last only 2 years. Its salvage value is $10,000 with an operating cost of $25,000 per year. Using an MARR value of 12% per year, which method should be selected?Two stamping machines are under consideration for purchase by a metal recycling company. The manual model will cost P1,250,000 to buy with an eight-year life and a P250,000 salvage value. Its annual operating costs will be P800,000. A computer-controlled model will cost P4,750,000 to buy and it will have a twelve-year life if upgraded at the end of year six for 750,000. Its terminal salvage value will be P1,150,000, with annual operating costs of P375,500 for labor and P125,000 for maintenance. The company's minimum attractive rate of return is 18%.Show the Cash Flow Diagram?
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