A company has 5 customer service representatives answering the phones. The probability that any one of the representatives will have a call at any given time is .4 Determine the probability of each, giving an exact decimal answer (do not round your answers): a. exactly 3 representatives have calls: b. all representatives have calls: c. more than 3 representatives have calls: d. at least 1 representative has a call:
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A company has 5 customer service representatives answering the phones. The
probability that any one of the representatives will have a call at any given time is .4Determine the probability of each, giving an exact decimal answer (do not round your answers):
a. exactly 3 representatives have calls:
b. all representatives have calls:
c. more than 3 representatives have calls:
d. at least 1 representative has a call:
Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and specify the other subparts (up to 3) you’d like answered.
n= number of trials = 5
p= probability of any one of the representatives will have a call at any given time= 0.4
Let, X= number of representatives have calls
So, X follows binomial distribution with n=5 and p=0.4
a)
b) All representatives have calls means X=5
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