A company creates wooden furniture to be sold at various retailers. This company claims that only 2.59% of their furniture are defective in some manner. Monicawould like to test this claim to see if the actual percentage of furniture that is defective is different than the company claims, using a = 0.01. She takes a sampleof 890 pieces of furniture, and observes that 47 of these furniture pieces are defective. Assume a normal sampling distribution.(a) What are the null and alternative hypotheses?Но: р0.0259 +HẠ: P0.0259 +(b) What is the test statistic? (Round your answer to 2 decimal places, if needed.)(c) Using the statistical table, what is the p-value? (Round your answer to 4 decimal places, if needed.)(d) Based on the p-value, Monica should rejectthe null hypothesis.(e) This data providessufficient evidence to conclude that the actual percentage of furniture that is defective is different than the company claims.

Given : Sample size (n) = 890 Let X : No. of defective furniture pieces X = 47 Significance level…

Answered: A company creates wooden furniture to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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