A committee with three voters votes over four alternatives x, y, z, w using alternative vote. We know that the preferences of the members are as follows: 1: wxyz 2: yxzw 3: Y e. 3 has as the least-preferred option y but we don't know the first three options. We also know that: xis the Condorcet winner x is the first alternative to be removed under alternative vote (the tie-breaking rule is the number of second choices) Find the three missing preferences of member 3. Note: enter ONLY three small letters, e.g., zxw, with no commas. spaces, etc.

A committee with three voters votes over four alternatives x, y, z, w using alternative vote. We know that the preferences of the members are as follows: 1: wxyz 2: yxzw 3: Y e. 3 has as the least-preferred option y but we don't know the first three options. We also know that: xis the Condorcet winner x is the first alternative to be removed under alternative vote (the tie-breaking rule is the number of second choices) Find the three missing preferences of member 3. Note: enter ONLY three small letters, e.g., zxw, with no commas. spaces, etc.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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