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A commercial airliner with four jet engines, each producing 79 kN of forward thrust, is in a steady, level cruise when engine number 3
suddenly fails. Determine the distance d (measured up or down on the figure) to the resultant of the three remaining engine thrust
vectors. Treat this as a two-dimensional problem. The distance d is positive if above the center line of the airplane, negative if below.
79 KN
*
8.7 m
11.8 m
11.8 m
8.7 m
79 KN
79 KN
Answer: d = i
3
T
2
S
1
m

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