A combinational circuit is divided into two sub-circuits N1 and N2 as shown. The truth table for N1 is given. Assume that the input combinations ABC=111 and ABC=000 never occur. 1- Complete the truth table. 2- Write D as minterms expansion and F as Maxterms expansion (Decimal notation). 3- Determine the Boolean expression of Z in terms of D, E and F as Maxterms expansion (Decimal notation). 4- Simplify the expressions of D, E and F as minimum Products of Sum. 5- Design the circuit of N₁ as minimum NOR-NOR implementation. B- C- 0 0 ABC D E 0 0 0 1 0 1 0 01 1 10 0 1 10 1 0 11 0 1 11 1 0 N₁ 0 1 [₂2] F 1 1 1 0 1 0 1 1 0 0 0 1 0 1 D E F N N₂ -Z

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Chapter1: Introduction
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A combinational circuit is divided into two sub-circuits N1 and N2 as shown. The truth table for
N1 is given. Assume that the input combinations ABC = 111 and ABC=000 never occur.
1- Complete the truth table.
2- Write D as minterms expansion and F as Maxterms expansion (Decimal notation).
3- Determine the Boolean expression of Z in terms of D, E and F as Maxterms expansion
(Decimal notation).
4- Simplify the expressions of D, E and F as minimum Products of Sum.
5- Design the circuit of N₁ as minimum NOR-NOR implementation.
0
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0
A
B-
C-
ABC D E
0 0
0
1
0
1
0
1
0
0
0
1
1
0
0
N₁
0
[1]
F
1 1
1 1
0
1
0
1
0
1
1
0
0
0
1
D
E
F
N
N₂
Z
Transcribed Image Text:A combinational circuit is divided into two sub-circuits N1 and N2 as shown. The truth table for N1 is given. Assume that the input combinations ABC = 111 and ABC=000 never occur. 1- Complete the truth table. 2- Write D as minterms expansion and F as Maxterms expansion (Decimal notation). 3- Determine the Boolean expression of Z in terms of D, E and F as Maxterms expansion (Decimal notation). 4- Simplify the expressions of D, E and F as minimum Products of Sum. 5- Design the circuit of N₁ as minimum NOR-NOR implementation. 0 0 0 0 A B- C- ABC D E 0 0 0 1 0 1 0 1 0 0 0 1 1 0 0 N₁ 0 [1] F 1 1 1 1 0 1 0 1 0 1 1 0 0 0 1 D E F N N₂ Z
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