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A column with a wide-flange section has a flange width b = 200 mm , height h = 200 mm , web thickness tw = 8 mm , and flange thickness tf = 12 mm (Figure 1). Calculate the stresses at a point 75 mm above the neutral axis if the section supports a tensile normal force N = 2.9 kN at the centroid, shear force V = 4.6 kN , and bending moment M = 4.8 kN⋅m as shown (Figure 2). Part A - Normal stress Calculate the normal stress at the point due to the internal normal force on the section. σnormal =? Part B - Shear stress Calculate the magnitude of the shear stress at the point due to the internal shear on the section. τ =?

A column with a wide-flange section has a flange width b = 200 mm , height h = 200 mm , web thickness tw = 8 mm , and flange thickness tf = 12 mm (Figure 1). Calculate the stresses at a point 75 mm above the neutral axis if the section supports a tensile normal force N = 2.9 kN at the centroid, shear force V = 4.6 kN , and bending moment M = 4.8 kN⋅m as shown (Figure 2). Part A - Normal stress Calculate the normal stress at the point due to the internal normal force on the section. σnormal =? Part B - Shear stress Calculate the magnitude of the shear stress at the point due to the internal shear on the section. τ =?

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A column with a wide-flange section has a flange width b = 200 mm , height h = 200 mm , web thickness tw = 8 mm , and flange thickness tf = 12 mm (Figure 1). Calculate the stresses at a point 75 mm above the neutral axis if the section supports a tensile normal force N = 2.9 kN at the centroid, shear force V = 4.6 kN , and bending moment M = 4.8 kN⋅m as shown (Figure 2).

Part A - Normal stress

Calculate the normal stress at the point due to the internal normal force on the section.

σnormal =?

Part B - Shear stress

Calculate the magnitude of the shear stress at the point due to the internal shear on the section.

τ =?
Figure < 2 of 2 > y N M V
Transcribed Image Text:Figure < 2 of 2 > y N M V
Figure 1 of 2 > y h -
Transcribed Image Text:Figure 1 of 2 > y h -
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