A college has 260 full-time employees that are currently covered under the school's health care plan. The average out-of-pocket cost for the employees on the plan is $1,940 with a standard deviation of $510. The college is performing an audit of its health care plan and has randomly selected 30 employees to analyze their out-of-pocket costs. a. Calculate the standard error of the mean. b. What is the probability that the sample mean will be less than $1,890? c. What is the probability that the sample mean will be more than $1,900? d. What is the probability that the sample mean will be between $1,965 and $2,005? a. The standard error of the mean is (Round to two decimal places as needed.) b. The probability that the sample mean will be less than 1,890 is. (Round to four decimal places as needed.) c. The probability that the sample mean will be more than 1,900 is (Round to four decimal places as needed.) d. The probability that the sample mean will be between 1,965 and 2,005 is (Round to four decimal places as needed.)

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**Title: Analyzing Employee Health Care Costs**

**Introduction:**

A college with 2,150 full-time employees is currently analyzing their health care plan. The average out-of-pocket cost for employees is $1,900, with a standard deviation of $250. A random sample of 30 employees has been selected to analyze their out-of-pocket costs.

**Problem Statements and Solutions:**

a. **Standard Error of the Mean:**
   - Calculate the standard error of the mean based on the given data.
   - Formula: SE = σ / √n
   - **Solution:** (Round to three decimal places)

b. **Probability Sample Mean < $1,890:**
   - Find the probability that the sample mean will be less than $1,890.
   - **Solution:** (Round to four decimal places)

c. **Probability Sample Mean > $1,900:**
   - Find the probability that the sample mean will be more than $1,900.
   - **Solution:** (Round to four decimal places)

d. **Probability Sample Mean Between $1,865 and $2,005:**
   - Find the probability that the sample mean will be between $1,865 and $2,005.
   - **Solution:** (Round to four decimal places)

**Conclusion:**

This analysis helps in understanding the distribution of out-of-pocket costs among employees and in making informed decisions about health care benefits. Calculating probabilities of different sample mean intervals provides insights into cost fluctuations and potential financial impacts on employees.
Transcribed Image Text:**Title: Analyzing Employee Health Care Costs** **Introduction:** A college with 2,150 full-time employees is currently analyzing their health care plan. The average out-of-pocket cost for employees is $1,900, with a standard deviation of $250. A random sample of 30 employees has been selected to analyze their out-of-pocket costs. **Problem Statements and Solutions:** a. **Standard Error of the Mean:** - Calculate the standard error of the mean based on the given data. - Formula: SE = σ / √n - **Solution:** (Round to three decimal places) b. **Probability Sample Mean < $1,890:** - Find the probability that the sample mean will be less than $1,890. - **Solution:** (Round to four decimal places) c. **Probability Sample Mean > $1,900:** - Find the probability that the sample mean will be more than $1,900. - **Solution:** (Round to four decimal places) d. **Probability Sample Mean Between $1,865 and $2,005:** - Find the probability that the sample mean will be between $1,865 and $2,005. - **Solution:** (Round to four decimal places) **Conclusion:** This analysis helps in understanding the distribution of out-of-pocket costs among employees and in making informed decisions about health care benefits. Calculating probabilities of different sample mean intervals provides insights into cost fluctuations and potential financial impacts on employees.
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