A coil in the shape of an equilateral triangle of side 10 cm lies in a vertical plane between the pole pieces of permanent magnet producing a horizontal magnetic field 20 mT. The torque acting on the coil when a current of 0.2 A is passed through it and its plane becomes parallel to the magnetic field will be √√xx10 Nm. The value of x is.........
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Q: A closed loop carrying a constant current is in a uniform magnetic field given by B =î – 2ĵ +k (T)…
A: please see the next step for solution
Q: A coil with a circular cross section having an area of 40cm has 40turns. When the coil is placed…
A: Area, A = 40 cm2 = 0.004 m2Number of turns, n = 40Magnetic field, B = 2 TMaximum torque, τ = 2×10-6…
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A: The given situation can be drawn as below,
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Q: A 100 turn circular coil of diameter 48 cm is placed in the earth's magnetic field 0.55 G, such that…
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