A coffee shops critic finds that a cup of coffee could be rated as too hot, too cold, or perfect. P(Hot) = 0.3 and P(cold) = 0.06. Find as a percentage: P(not hot) = P(not cold) = P(perfect) = P(not perfect) = P(cold) + P(not cold) = P(perfect) - P(not cold) + P(hot) =
A coffee shops critic finds that a cup of coffee could be rated as too hot, too cold, or perfect. P(Hot) = 0.3 and P(cold) = 0.06. Find as a percentage: P(not hot) = P(not cold) = P(perfect) = P(not perfect) = P(cold) + P(not cold) = P(perfect) - P(not cold) + P(hot) =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:A coffee shops critic finds that a cup of coffee could be rated as too hot, too cold, or
perfect. P(Hot) = 0.3 and P(cold) = 0.06. Find as a percentage:
P(not hot) =
P(not cold) =
P(not perfect)=
P(perfect) - P(not cold) + P(hot) =
P(perfect) =
P(cold) + P(not cold) =
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