A coffee pot has the shape of a cylinder with radius 5 inches, as shown in the figure. Let h be the depth of the coffee in the pot, measured in inches, where h is a function of time t, measured in seconds. The volume V, of coffee in the pot is 5 in dV = -57 h cubic inches per second. dt changing at the rate of dh Show that dt (V = ar²h and SA= 2arh+2xr² ) 5 00

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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A coffee pot has the shape of a cylinder with radius 5 inches, as shown in the figure. Let h be the depth of the coffee in the pot, measured in inches, where h is a function of time t, measured in seconds. The volume V, of coffee in the pot is changing at the rate of dV/dt = -5(pie) (h)1/2 cubic inches per second.

A coffee pot has the shape of a cylinder with radius 5 inches, as shown in the figure.
Let h be the depth of the coffee in the pot, measured in inches, where h is a
function of time t, measured in seconds. The volume V, of coffee in the pot is
5 in
dV
changing at the rate of
= -57 h cubic inches per second.
dt
dh
Show that
dt
(V = ar²h and SA=2rh+2rr' )
5
h in
Transcribed Image Text:A coffee pot has the shape of a cylinder with radius 5 inches, as shown in the figure. Let h be the depth of the coffee in the pot, measured in inches, where h is a function of time t, measured in seconds. The volume V, of coffee in the pot is 5 in dV changing at the rate of = -57 h cubic inches per second. dt dh Show that dt (V = ar²h and SA=2rh+2rr' ) 5 h in
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