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A coaxial cable (e.g. RG-402U semirigid cable) has an inner conductor diameter of 0.91 mm and a dielectric diameter (equal to the inner diameter of the outer conductor) of 3.02 mm. Both conductors are copper, and the dielectric material is Teflon. Compute the R, L, G, and C parameters of this line at 1 GHz. Use the expressions and material properties from the figure below or lecture note. L C R G COAX μ 2π In Σπε Inb/a Rs (1 2π b a + 2π w€" In b/a Material properties: Copper: Conductivity = Characteristic impedance Loss Propagation constant Teflon: Loss tan(8) = 0.0004 € = 2.08 Er € = €0 €r = €0€, tan(8) €" Rs Zo = = = 5.8 x 107 S/m ζω μο 2σ R+ jwL G + jwC L L R + 12 ( ₁ √ ² + G√ ² ) = ² ( 2² 6 + 0²₁). £ 周 GZo 2 Zo B≈w√LC.

A coaxial cable (e.g. RG-402U semirigid cable) has an inner conductor diameter of 0.91 mm and a dielectric diameter (equal to the inner diameter of the outer conductor) of 3.02 mm. Both conductors are copper, and the dielectric material is Teflon. Compute the R, L, G, and C parameters of this line at 1 GHz. Use the expressions and material properties from the figure below or lecture note. L C R G COAX μ 2π In Σπε Inb/a Rs (1 2π b a + 2π w€" In b/a Material properties: Copper: Conductivity = Characteristic impedance Loss Propagation constant Teflon: Loss tan(8) = 0.0004 € = 2.08 Er € = €0 €r = €0€, tan(8) €" Rs Zo = = = 5.8 x 107 S/m ζω μο 2σ R+ jwL G + jwC L L R + 12 ( ₁ √ ² + G√ ² ) = ² ( 2² 6 + 0²₁). £ 周 GZo 2 Zo B≈w√LC.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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(3) A coaxial cable (e.g. RG-402U semirigid cable) has an inner conductor diameter of 0.91 mm and a dielectric diameter (equal to the inner diameter of the outer conductor) of 3.02 mm. Both conductors are copper, and the dielectric material is Teflon. Compute the R, L, G, and C parameters of this line at 1 GHz. Use the expressions and material properties from the figure below or lecture note. L C R G COAX b fe -In 2π a Σπε Inb/a Rs + 2π a 2πTWE" Inb/a Material properties: Copper: Conductivity = Characteristic impedance Teflon: Loss tan (8) = 0.0004 € = 2.08 €' = €0€r Loss Rs = €" Zo = = 5.8 x 107 S/m ιωμα 2σ = €0€, tan(8) R+jwL VG+jwC ~ L 1 R α ~ 11 ( ²√² + 0 √ ² ) = ² ( 2² 6 + 0²0). G₁ GZo L Zo B≈w√LC, Propagation constant Figure 2 - Coax line with the expressions and the materials properties. Bonus: Use the results to find the characteristic impedance and attenuation(dielectric loss and conductance loss) of the line at 1 GHz using the formula from the figure(in red box).
Transcribed Image Text:(3) A coaxial cable (e.g. RG-402U semirigid cable) has an inner conductor diameter of 0.91 mm and a dielectric diameter (equal to the inner diameter of the outer conductor) of 3.02 mm. Both conductors are copper, and the dielectric material is Teflon. Compute the R, L, G, and C parameters of this line at 1 GHz. Use the expressions and material properties from the figure below or lecture note. L C R G COAX b fe -In 2π a Σπε Inb/a Rs + 2π a 2πTWE" Inb/a Material properties: Copper: Conductivity = Characteristic impedance Teflon: Loss tan (8) = 0.0004 € = 2.08 €' = €0€r Loss Rs = €" Zo = = 5.8 x 107 S/m ιωμα 2σ = €0€, tan(8) R+jwL VG+jwC ~ L 1 R α ~ 11 ( ²√² + 0 √ ² ) = ² ( 2² 6 + 0²0). G₁ GZo L Zo B≈w√LC, Propagation constant Figure 2 - Coax line with the expressions and the materials properties. Bonus: Use the results to find the characteristic impedance and attenuation(dielectric loss and conductance loss) of the line at 1 GHz using the formula from the figure(in red box).
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