(3) A coaxial cable (e.g. RG-402U semirigid cable) has an inner conductor diameter of 0.91 mm and a dielectricdiameter (equal to the inner diameter of the outer conductor) of 3.02 mm. Both conductors are copper, and thedielectric material is Teflon. Compute the R, L, G, and C parameters of this line at 1 GHz. Use the expressionsand material properties from the figure below or lecture note.LCRGCOAXbfe-In2π aΣπεInb/aRs+2π a2πTWE"Inb/aMaterial properties:Copper:Conductivity =CharacteristicimpedanceTeflon:Loss tan (8) = 0.0004€ = 2.08€' = €0€rLossRs =€"Zo == 5.8 x 107 S/mιωμα2σ= €0€, tan(8)R+jwLVG+jwC~L1Rα ~11 ( ²√² + 0 √ ² ) = ² ( 2² 6 + 0²0).G₁GZoLZoB≈w√LC,PropagationconstantFigure 2 - Coax line with the expressions and the materials properties.Bonus: Use the results to find the characteristic impedance and attenuation(dielectric loss and conductance loss)of the line at 1 GHz using the formula from the figure(in red box).

According to the question, for the given coaxial cable we need to find the parameters R, L, C, G at…

A coaxial cable (e.g. RG-402U semirigid cable) has an inner conductor diameter of 0.91 mm and a dielectric diameter (equal to the inner diameter of the outer conductor) of 3.02 mm. Both conductors are copper, and the dielectric material is Teflon. Compute the R, L, G, and C parameters of this line at 1 GHz. Use the expressions and material properties from the figure below or lecture note. L C R G COAX μ 2π In Σπε Inb/a Rs (1 2π b a + 2π w€" In b/a Material properties: Copper: Conductivity = Characteristic impedance Loss Propagation constant Teflon: Loss tan(8) = 0.0004 € = 2.08 Er € = €0 €r = €0€, tan(8) €" Rs Zo = = = 5.8 x 107 S/m ζω μο 2σ R+ jwL G + jwC L L R + 12 ( ₁ √ ² + G√ ² ) = ² ( 2² 6 + 0²₁). £ 周 GZo 2 Zo B≈w√LC.

A coaxial cable (e.g. RG-402U semirigid cable) has an inner conductor diameter of 0.91 mm and a dielectric diameter (equal to the inner diameter of the outer conductor) of 3.02 mm. Both conductors are copper, and the dielectric material is Teflon. Compute the R, L, G, and C parameters of this line at 1 GHz. Use the expressions and material properties from the figure below or lecture note. L C R G COAX μ 2π In Σπε Inb/a Rs (1 2π b a + 2π w€" In b/a Material properties: Copper: Conductivity = Characteristic impedance Loss Propagation constant Teflon: Loss tan(8) = 0.0004 € = 2.08 Er € = €0 €r = €0€, tan(8) €" Rs Zo = = = 5.8 x 107 S/m ζω μο 2σ R+ jwL G + jwC L L R + 12 ( ₁ √ ² + G√ ² ) = ² ( 2² 6 + 0²₁). £ 周 GZo 2 Zo B≈w√LC.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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