A coaxial cable contains an insulating material of conductivity σ₁ in its upper half and another material of conductivity σ₂ in its lower half (similar to the situation shown later in Figure 6.19b). If the radius of the central wire is a and that of the sheath is b, show that the leakage resistance of length of the cable is Answer: Proof. R 1 πl (σ₁ + σ₂) In b

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A coaxial cable contains an insulating material of conductivity σ₁ in its upper half and another material of conductivity σ₂ in its lower half (similar to the situation shown later in Figure 6.19b). If the radius of the central wire is \( a \) and that of the sheath is \( b \), show that the leakage resistance of length \( \ell \) of the cable is

\[
R = \frac{1}{\pi \ell (\sigma_1 + \sigma_2)} \ln \frac{b}{a}
\]

**Answer:** Proof.
Transcribed Image Text:A coaxial cable contains an insulating material of conductivity σ₁ in its upper half and another material of conductivity σ₂ in its lower half (similar to the situation shown later in Figure 6.19b). If the radius of the central wire is \( a \) and that of the sheath is \( b \), show that the leakage resistance of length \( \ell \) of the cable is \[ R = \frac{1}{\pi \ell (\sigma_1 + \sigma_2)} \ln \frac{b}{a} \] **Answer:** Proof.
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