A coaxial cable consists of alternating coaxial cylinders of conducting and insulating material. Coaxial cabling is the primary type of cabling used by the cable television industry and is also widely used for computer networks such as Ethernet, on account of its superior ability to transmit large volumes of electrical signal with minimum distortion. Like all other kinds of cables, however, coaxial cables also have some self-inductance that has undesirable effects, such as producing some distortion and heating. Figure O < 1 of 1 > € ▾ Part A Consider a long coaxial cable made of two coaxial cylindrical conductors that carry equal currents I in opposite directions (see figure). The inner cylinder is a small solid conductor of radius a. The outer cylinder is a thin walled conductor of outer radius b, electrically insulated from the inner conductor. Calculate the self-inductance per unit length of this coaxial cable. (Figure 1) (L is the inductance of part of the cable and I is the length of that part.) Due to what is known as the "skin effect", the current I flows down the (outer) surface of the inner conducting cylinder and back along the inner surface of the outer conducting cylinder. However, you may ignore the thickness of the outer cylinder. Express your answer in terms of some or all the variables I, a, b, and μo, the permeability of free space. ▸ View Available Hint(s) ΟΙ ΑΣΦ Submit Provide Feedback P ? Next >
A coaxial cable consists of alternating coaxial cylinders of conducting and insulating material. Coaxial cabling is the primary type of cabling used by the cable television industry and is also widely used for computer networks such as Ethernet, on account of its superior ability to transmit large volumes of electrical signal with minimum distortion. Like all other kinds of cables, however, coaxial cables also have some self-inductance that has undesirable effects, such as producing some distortion and heating. Figure O < 1 of 1 > € ▾ Part A Consider a long coaxial cable made of two coaxial cylindrical conductors that carry equal currents I in opposite directions (see figure). The inner cylinder is a small solid conductor of radius a. The outer cylinder is a thin walled conductor of outer radius b, electrically insulated from the inner conductor. Calculate the self-inductance per unit length of this coaxial cable. (Figure 1) (L is the inductance of part of the cable and I is the length of that part.) Due to what is known as the "skin effect", the current I flows down the (outer) surface of the inner conducting cylinder and back along the inner surface of the outer conducting cylinder. However, you may ignore the thickness of the outer cylinder. Express your answer in terms of some or all the variables I, a, b, and μo, the permeability of free space. ▸ View Available Hint(s) ΟΙ ΑΣΦ Submit Provide Feedback P ? Next >
College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Self-Inductance of a Coaxial Cable
A coaxial cable consists of alternating coaxial cylinders of
conducting and insulating material. Coaxial cabling is the
primary type of cabling used by the cable television industry
and is also widely used for computer networks such as
Ethernet, on account of its superior ability to transmit large
volumes of electrical signal with minimum distortion. Like all
other kinds of cables, however, coaxial cables also have
some self-inductance that has undesirable effects, such as
producing some distortion and heating.
Figure
O
I
I
<
1 of 1
€
Part A
Submit
Provide Feedback
Consider a long coaxial cable made of two coaxial cylindrical conductors that carry equal currents I in opposite directions (see figure). The inner
cylinder is a small solid conductor of radius a. The outer cylinder is a thin walled conductor of outer radius b, electrically insulated from the inner
conductor. Calculate the self-inductance per unit length of this coaxial cable. (Figure 1) (L is the inductance of part of the cable and I is the length
1
of that part.) Due to what is known as the "skin effect", the current I flows down the (outer) surface of the inner conducting cylinder and back along the
inner surface of the outer conducting cylinder. However, you may ignore the thickness of the outer cylinder.
Express your answer in terms of some or all the variables I, a, b, and μo, the permeability of free space.
► View Available Hint(s)
ΑΣΦ
W
<
?
14 of 15
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