a coach has 6 players that will join track and field. the random variable that is being studied is x,the number of players that will win. the probability function for this is shown in the tables
a coach has 6 players that will join track and field. the random variable that is being studied is x,the number of players that will win. the probability function for this is shown in the tables
a coach has 6 players that will join track and field. the random variable that is being studied is x,the number of players that will win. the probability function for this is shown in the tables
a coach has 6 players that will join track and field. the random variable that is being studied is x,the number of players that will win. the probabilityfunction for this is shown in the tables
Transcribed Image Text:document?
Solution:
u given day, majority of the stocks will increase in value.
Majority of the stocks means we will consider stocks(X) which is minimum more than haif from
O to 5. Hence, we need to find P[x23].
Plx23]3DP[x = 3]+ P[x=D41+ PLx 5]
=f(3)+ f(4) +(5)
0.10+0.05 + 0.01
where P[x 2 3] = P[x 3] + P(x 4] + Plx = 5] = f(3) + f(4) + f(5) = 0.10 +005 +001= 0.16
Therefore, the probability that the majority of the stocks will increase in value is 0.16 (or 16%).
2. A coach has 6 players that will join track and field. The random variable that is being studied is X,
the number of players that will win. The probability function for this variable is shown in the table
below..
2.
)%3DP[X%3Dx]
T0.40
0.24
0.19
0.1
0.05
0.02
Question; Find the probability that the majority of the players will win the play?
Solution and answer:
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Transcribed Image Text:Where P(x 31- P(x 31 + Plx = 4) + Plx51 -((3)+1(4)+ S-10s 454
Therefore, the probability that the majority of the stocks will increase in value is .s or 1)
A coach has 6 players that will join track and field. The random vanable that is
the number of players that will win. The probability function for this variatle is shown n the table
below.
sudied is X,
1.
2.
3.
4.
0.40
0.24
0.19
0.05
0.1
0.02
[x=x]d3D(3
en: Find the probability that the majority of the players will win the play?
and answer:
tattoos they had
ra
Expression, rule, or law that gives the relationship between an independent variable and dependent variable. Some important types of functions are injective function, surjective function, polynomial function, and inverse function.
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Solution:
u given day, majority of the stocks will increase in value.
Majority of the stocks means we will consider stocks(X) which is minimum more than haif from
O to 5. Hence, we need to find P[x23].
Plx23]3DP[x = 3]+ P[x=D41+ PLx 5]
=f(3)+ f(4) +(5)
0.10+0.05 + 0.01
where P[x 2 3] = P[x 3] + P(x 4] + Plx = 5] = f(3) + f(4) + f(5) = 0.10 +005 +001= 0.16
Therefore, the probability that the majority of the stocks will increase in value is 0.16 (or 16%).
2. A coach has 6 players that will join track and field. The random variable that is being studied is X,
the number of players that will win. The probability function for this variable is shown in the table
below..
2.
)%3DP[X%3Dx]
T0.40
0.24
0.19
0.1
0.05
0.02
Question; Find the probability that the majority of the players will win the play?
Solution and answer:
tattoos they had which](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a88ad94-8ae9-46ee-82a8-30efc05652a5%2F7c4f4058-5b47-4fce-998b-a7e0ee1cce63%2F5al27zi_processed.jpeg&w=3840&q=75)
![Where P(x 31- P(x 31 + Plx = 4) + Plx51 -((3)+1(4)+ S-10s 454
Therefore, the probability that the majority of the stocks will increase in value is .s or 1)
A coach has 6 players that will join track and field. The random vanable that is
the number of players that will win. The probability function for this variatle is shown n the table
below.
sudied is X,
1.
2.
3.
4.
0.40
0.24
0.19
0.05
0.1
0.02
[x=x]d3D(3
en: Find the probability that the majority of the players will win the play?
and answer:
tattoos they had
ra](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a88ad94-8ae9-46ee-82a8-30efc05652a5%2F7c4f4058-5b47-4fce-998b-a7e0ee1cce63%2Finlc5r_processed.jpeg&w=3840&q=75)
