A closed traverse has the following data: LINE / LENGTH (m) / Bearing AB / 126.00 m/ N 35° E BC / 233.00 m/ S 10° E CA / 170.00 m/ N 41° W By adjusting the traverse using Transit Rule, 1. Find the corrected length of line BC. A. 233.800 m B. 233.969 m C. 232.109 m D. 231.967 m 2. Find the corrected azimuth from North of line CA. A. 290° 12' 50" B. 315° 23' 27" C. 289° 25' 07" D. 318° 43' 19"

A closed traverse has the following data: LINE / LENGTH (m) / Bearing AB / 126.00 m/ N 35° E BC / 233.00 m/ S 10° E CA / 170.00 m/ N 41° W By adjusting the traverse using Transit Rule, 1. Find the corrected length of line BC. A. 233.800 m B. 233.969 m C. 232.109 m D. 231.967 m 2. Find the corrected azimuth from North of line CA. A. 290° 12' 50" B. 315° 23' 27" C. 289° 25' 07" D. 318° 43' 19"

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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For a traverse containing 10 sides, what would be the correction applied for the first side, if it consists of a closing error of +1.92? O a. 1.902 O b. 0.192 O c. 19.2 O d. 19.0
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Direction: Given the following data on the table. Fill up the needed data. Balance the traverse by transit rule. Solve the area by DPD or DMD. Sketch the traverse. All values must be in decimal places. COMPUTED ADJUSTED DEPARTURE LIN ADJUST ADJUST DISTAN СЕ (M) AZIMUT COMPUTED ADJUSTED LATITUDE ADJUST ED AZIMUT BEARIN DPD DOUBLE E G LATITUDE DEPARTURE ED DISTAN СЕ ED AREA (from S) BEARIN H (nearest (nearest minute) minute) +NL -SL +ED -WD +NL -SL +ED -WD АВ E S 70-29 N 10-00 650.00 ВС 895.00 CD S 26-28 315.00 DE S 65-33 W EA 875.00 410.00 N 45-31 W ТОTAL LEC : RP (nearest hundred) AREA ..
A closed traverse has the following data: LINE / LENGTH (m) / Bearing AB / 126.00 m / N 35° E BC / 233.00 m/ S 10° E CA / 170.00 m/ N 41° W 1. || Find the departure disclosure of the traverse. A. 1.201 m B. 2.423 m C. 1.006 m D. 2.321 m 2. Find the latitude disclosure. A. 1.267 m B. 1.889 m C. 2.054 m D. 1.560 m
2. Traverse data are tabulated as shown. Adjust the lengths and bearing angles to close the traverse. Compute the perimeter (summation of the lengths) of the adjusted traverse. LENGTH BEARINGS LINE (m) D S 85 30 E S 2 AB 495.85 ВС 875.34 15 W CD 890.45 N 76 44 W DA 1134.16 N 36 9 E
TRANSIT RULE. pls make use of table and draw the traverse
Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the area of the traverse using DMD Method. Line Length Bearing AB 382.500 m Due East BC 248.780 m S 89°25’ E CD Unknown S 27°45’ W DE 220.420 m Unknown EA 443.490 m N 40°08’ W Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
A parcel of land has been surveyed in the field and the lengths and bearings of the various sides are shown. Compute for the error in departure. +0.03870 -0.03780 +0.03780 -0.03870 LINES AB BC CD DA BEARING N 53°27' E S 66°54' E S 29°08' W N 52°00' W DISTANCES 59.82 m 70.38 m 76.62 m 95.75 m
3456 7 8910 200 b00 Find Po FiL assume i 8/
With complete solution and drawing
1. From the field notes of a closed traverse show below, adjust the traverse. LINES BEARING DISTANCES AB Due North 401 ВС N 45° E 797 CD S 60° E 700 DE S 200 W 600 EA S 86° 59' W 966.34 a. Solve for the Latitude and Departure b. Solve for the Adjusted and Balanced Departure and Latitude using compass/transit rule (specify your choice) c. Solve for the Balanced Length and Bearing d. Using the adjusted departure and latitude, calculate the area of the traverses using DMD/DPD method. (Specify your choice)