A closed-loop shown in the figure consi sts of N the number of turns and staying in a uniform magnetic field given by B = -î + ĵ+ k (T). Ignore the magnetic field created by the current- carrying loop. Find the magnitude of the magnetic force exerted on BC wire (in units of Newton), the magneti c dipole moment i of the current loop (in units of A.m?), and the torque acting on the loop (in units of N.m) in terms of unit vectors. What is the potential energy of the loop in units of Joule? N = 10;I = 1 A; a = 1 cm

Elements Of Electromagnetics
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14)
y
A
a
B
a
E
C
D
a
A closed-loop shown in the figure consists of N the number of turns and staying
in a uniform magnetic field given by B = -î +j + k (T). Ignore the magnetic
field created by the current- carrying loop. Find the magnitude of the magnetic
force exerted on BC wire (in units of Newton), the magnetic dipole moment i of
the current loop (in units of A.m?), and the torque acting on the loop (in units of
N.m) in terms of unit vectors. What is the potential energy of the loop in units of
Joule?
N = 10;I = 1 A; a = 1 cm
a) Fac = 1 x 10-2(-i + i); ji = 1 x 10-3 (i +j +), 7 = 1 x 10-3 (i + + 2k); U = -5 x 10-
b) Fac = 1x 10-(-i- R); ū = 1 × 10-3 (i + j +); # = 1 × 10- ( -+ 2k); U = -5 x 10-
c) Fac = 1x 10-2 (i + j); i = 1x 10- (i+ j+k); i = 1 x 10- (-- + 2k); U = -5 x 10-4
BC
d) Fac = 1 x 10-2(i - ); ji = 1 x 10-3 (i + j+k); i = 1x 10 (-i+j+ 2k); U = o
e) Fac = 1x 10-2 (e + R); µ = 1 x 10-3 (t+ j+R); i = 1 x 10-3 (21 --R); U = -5 x 10-4
Transcribed Image Text:14) y A a B a E C D a A closed-loop shown in the figure consists of N the number of turns and staying in a uniform magnetic field given by B = -î +j + k (T). Ignore the magnetic field created by the current- carrying loop. Find the magnitude of the magnetic force exerted on BC wire (in units of Newton), the magnetic dipole moment i of the current loop (in units of A.m?), and the torque acting on the loop (in units of N.m) in terms of unit vectors. What is the potential energy of the loop in units of Joule? N = 10;I = 1 A; a = 1 cm a) Fac = 1 x 10-2(-i + i); ji = 1 x 10-3 (i +j +), 7 = 1 x 10-3 (i + + 2k); U = -5 x 10- b) Fac = 1x 10-(-i- R); ū = 1 × 10-3 (i + j +); # = 1 × 10- ( -+ 2k); U = -5 x 10- c) Fac = 1x 10-2 (i + j); i = 1x 10- (i+ j+k); i = 1 x 10- (-- + 2k); U = -5 x 10-4 BC d) Fac = 1 x 10-2(i - ); ji = 1 x 10-3 (i + j+k); i = 1x 10 (-i+j+ 2k); U = o e) Fac = 1x 10-2 (e + R); µ = 1 x 10-3 (t+ j+R); i = 1 x 10-3 (21 --R); U = -5 x 10-4
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