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A closed box whose length is twice its width is to have a surface area of 192 square inches. Find the dimension of the box when the volume is maximum O a. 2 by 4 by 44/3 inches Ob.1 by 2 by 94/3 inches O.4 by 8 by 16/3 inches O d.3 by 9 by 23/4 inches

A closed box whose length is twice its width is to have a surface area of 192 square inches. Find the dimension of the box when the volume is maximum O a. 2 by 4 by 44/3 inches Ob.1 by 2 by 94/3 inches O.4 by 8 by 16/3 inches O d.3 by 9 by 23/4 inches

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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QUESTION 2 A closed box whose length is twice its width is to have a surface area of 192 square inches. Find the dimension of the box when the volume is maximum. O a. 2 by 4 by 44/3 inches Ob. 1 by 2 by 94/3 inches O. 4 by 8 by 16/3 inches O d. 3 by 9 by 23/4 inches
Transcribed Image Text:QUESTION 2 A closed box whose length is twice its width is to have a surface area of 192 square inches. Find the dimension of the box when the volume is maximum. O a. 2 by 4 by 44/3 inches Ob. 1 by 2 by 94/3 inches O. 4 by 8 by 16/3 inches O d. 3 by 9 by 23/4 inches
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