A clock with an hour hand that is 18 inches long is hanging on a wall. At noon, the vertical distance between the tip of the hour hand and the ceiling is 25 inches. At 3 P.M., the distance is 43 inches; at 6 P.M., 61 inches; at 9 P.M., 43 inches; and at midnight the distance is again 25 inches. If f (x) represents he distance between the tip of the hour hand and the ceiling x hours after noon, write the function that epresents this situation in the form of f(x) = acos(bx) + d. о f(x) = -18 cos Of(x)=-18 cos(x) + 43 +43 Of(x)=-43 cos (*) +18 Of(x)=-43 cos (x) + +18

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Understanding Periodic Functions: A Practical Example with a Clock's Hour Hand

Consider a clock with an hour hand that is 18 inches long, mounted vertically on a wall. At different times of the day, there will be varying distances between the tip of the hour hand and the ceiling. This problem explores how to model such a situation using a cosine function.

#### Problem Description:
- **At noon**: The vertical distance between the tip of the hour hand and the ceiling is **25 inches**.
- **At 3 PM**: The distance is **43 inches**.
- **At 6 PM**: The distance is **61 inches**.
- **At 9 PM**: The distance is **43 inches** again.
- **At midnight**: The distance returns to **25 inches**.

The goal is to represent the distance between the tip of the hour hand and the ceiling, \( f(x) \), as a function of time, \( x \), where \( x \) is the number of hours after noon. The function is to be expressed in the form:

\[ f(x) = a \cos(bx) + d \]

#### Answer Choices to Consider:
1. \[ f(x) = -18 \cos\left(\frac{\pi}{12} x\right) + 43 \]
2. \[ f(x) = -18 \cos\left(\frac{\pi}{6} x\right) + 43 \]
3. \[ f(x) = -43 \cos\left(\frac{\pi}{12} x\right) + 18 \]
4. \[ f(x) = -43 \cos\left(\frac{\pi}{6} x\right) + 18 \]

### Explanation:
To solve for \( f(x) \), we need to determine the parameters \( a \), \( b \), and \( d \) by considering the behavior of the hour hand.

1. **Amplitude (a)**:
   - The maximum deviation from the average distance (centerline) of 43 inches is 18 inches. Therefore, \( a = -18 \) (the negative sign reflects the phase shift to match the starting point conditions).

2. **Period (P)**:
   - The hour hand completes a full cycle every 12 hours. Hence, the period \( P \) is 12.
   - Using the period to calculate \(
Transcribed Image Text:### Understanding Periodic Functions: A Practical Example with a Clock's Hour Hand Consider a clock with an hour hand that is 18 inches long, mounted vertically on a wall. At different times of the day, there will be varying distances between the tip of the hour hand and the ceiling. This problem explores how to model such a situation using a cosine function. #### Problem Description: - **At noon**: The vertical distance between the tip of the hour hand and the ceiling is **25 inches**. - **At 3 PM**: The distance is **43 inches**. - **At 6 PM**: The distance is **61 inches**. - **At 9 PM**: The distance is **43 inches** again. - **At midnight**: The distance returns to **25 inches**. The goal is to represent the distance between the tip of the hour hand and the ceiling, \( f(x) \), as a function of time, \( x \), where \( x \) is the number of hours after noon. The function is to be expressed in the form: \[ f(x) = a \cos(bx) + d \] #### Answer Choices to Consider: 1. \[ f(x) = -18 \cos\left(\frac{\pi}{12} x\right) + 43 \] 2. \[ f(x) = -18 \cos\left(\frac{\pi}{6} x\right) + 43 \] 3. \[ f(x) = -43 \cos\left(\frac{\pi}{12} x\right) + 18 \] 4. \[ f(x) = -43 \cos\left(\frac{\pi}{6} x\right) + 18 \] ### Explanation: To solve for \( f(x) \), we need to determine the parameters \( a \), \( b \), and \( d \) by considering the behavior of the hour hand. 1. **Amplitude (a)**: - The maximum deviation from the average distance (centerline) of 43 inches is 18 inches. Therefore, \( a = -18 \) (the negative sign reflects the phase shift to match the starting point conditions). 2. **Period (P)**: - The hour hand completes a full cycle every 12 hours. Hence, the period \( P \) is 12. - Using the period to calculate \(
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