A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 14 subjects had a mean wake time of 97.4 min and a standard deviation of 40.7 min. Assume that the 14 sample values appear to be from a normally distributed population and construct a 98% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate.
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Confidence interval: Since the population standard deviation is unknown, t distribution can be used…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: n = 22x¯ = 77.9s = 24.690% confidence interval for μ. claim : μ ≠ 100
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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Q: Find the confidence interval estimate. enter your response here min<σ<enter your response here min…
A: It is given that Sample mean = 94.7Sample standard deviation = 44.2Confidence level = 95%Sample size…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Given data: Sample mean = 101.1min Sample size = 13 Sample standard deviation = 20.8 min Confidence…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given That The sample size is n=16 The sample mean is X=91.6 The sample standard deviation is s=40.1…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: It is given that sample mean is 72.3 min and standard deviation is 21.2 min.
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Obtain the 90% confidence interval estimate of the mean wake time for a population with the…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A:
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: The degrees of freedom is, df=n-1=23-1=22 The degrees of freedom is 22. Critical value for χU2 : The…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: The sample size is 16, the sample mean is 97.8 and the sample standard deviation is 22.6.
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given : Sample Size (n) = 26 standard deviation(s) = 40.7 The level of significance (L) =0.10…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: From the provided information, Sample size (n) = 29 Sample mean (x̅) = 93.7 min Sample standard…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given: We have Sample Size (n)=20 Sample Mean (X¯)=91.3 Sample Standard Deviation (s) =40.5 90%…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A:
Q: drug for treating insomnia in older subjects. Before treatment, 13 subjects had a mean wake time of…
A: Given Xbar=95.3 Standard deviation=23.2
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Introduction: The 100 (1 – α) % confidence interval for the population standard deviation, σ, is the…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A:
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given data,n=15x=91.8s=42.7α=0.10t-critical value at α=0.10 and df=14 is tc=1.761
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given n=29, s=44.6=sample standard deviations Level of significance ɑ=0.10
Q: Find the confidence interval estimate. min <a<min (Round to two decimal places as needed.)
A:
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: From the given information we find the confidence interval.
Q: clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older…
A:
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: From the given information, Sample size n =24 Sample mean, x̅=100.3. Sample standard deviation,…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: The sample size is 21, sample mean is 98.7, and sample standard deviation is 22.9. The degrees of…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Sample size, n=20 Sample standard deviation, s = 43.9
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given: Sample MeanX=93.8Sample Standard Deviations=44.8Sample Sizen=26
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: GIVEN DATA n = 18 x¯ = 96.9s = 22.295% ci for μ.
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Given: x¯=100.3n=17s=20.3c=90%=0.90
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A:
Q: clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older…
A: Given n=26, x̄=95.2, s=40.7 ɑ=0.02
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Find critical values for chi-square distribution: Refer chi-square table to find the critical…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Find critical values for chi-square distribution: Refer chi-square table to find the critical…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: It is given that, The sample size, n is 13. Before treatment Sample mean = 100.0 min. After…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Given information Sample size (n) = 21 Sample mean x̅ = 78.5 min Standard deviation (s) = 24.8 min…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Obtain the 90% confidence interval estimate of the standard deviation of the wake times for a…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: A sample of 12 subjects had a mean wake time of 96.1 min and a standard deviation of 43.4 min. The…
Q: a clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: The objective of this question is to construct a 95% confidence interval for the standard deviation…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: The sample size is 25, sample mean is 97.6, sample standard deviation is 21.8. The degrees of…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given that Sample size n = 21 Sample SD s = 43.5 We have to find the 90% confidence interval for…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Given, n=23 Before treatment Mean =101.0 min After treatment Mean =91.4 min s=21.4 min Confidence…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given: Sample size(n)=15Standard deviation(s)=20.4Sample Mean(x¯)=95.7Population mean(μ)=100
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A:
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- A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 26 subjects had a mean wake time of 97.5 min and a standard deviation of 43.3 min. Assume that the 26 sample values appear to be from a normally distributed population and construct a 98% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective?A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 24 subjects had a mean wake time of 90.7 min and a standard deviation of 41.3 min. Assume that the 24 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. ___min <σ<___ minA clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 20 subjects had a mean wake time of 101.0 min. After treatment, the 20 subjects had a mean wake time of 97.8 min and a standard deviation of 23.1 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 101.0 min before the treatment? Does the drug appear to be effective? Construct the 90% confidence interval estimate of the mean wake time for a population with the treatment. What does the result suggest about the mean wake time of 01.0min before the treatment? Does the drug appear to be effective?
- A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 20 subjects had a mean wake time of 105.0 min. After treatment, the 20 subjects had a mean wake time of 82.5 min and a standard deviation of 22.5 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 105.0 min before the treatment? Does the drug appear to be effective? Construct the 90% confidence interval estimate of the mean wake time for a population with the treatment. ???? min<μ<???? minA clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 16 subjects had a mean wake time of 92.6 min and a standard deviation of 40.2 min. Assume that the 16 sample values appear to be from a normally distributed population and construct a 98% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. minBone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of womenA clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 24 subjects had a mean wake time of 105.0 min. After treatment, the 24 subjects had a mean wake time of 84.6 min and a standard deviation of 23.4 min. Assume that the 24 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 105.0 min before the treatment? Does the drug appear to be effective? Construct the 95% confidence interval estimate of the mean wake time for a population with the treatment. min < µ< min (Round to one decimal place as needed.)A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 23 subjects had a mean wake time of 93.6 min and a standard deviation of 43.8 min. Assume that the 23 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. minA clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 20 subjects had a mean wake time of 92.5 min and a standard deviation of 43.9 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. minA clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 16 subjects had a mean wake time of 105.0 min. After treatment, the 16 subjects had a mean wake time of 95.3 min and a standard deviation of 23.5 min. Assume that the 16 sample values appear to be from a normally distributed population and construct a 99% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 105.0 min before the treatment? Does the drug appear to be effective?A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 26 subjects had a mean wake time of 91.3 min and a standard deviation of 43.4 min. Assume that the 26 sample values appear to be from a normally distributed population and construct a 98% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Question content area bottom Part 1 Find the confidence interval estimate.A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 11 subjects had a mean wake time of 97.2 min and a standard deviation of 43.4 min. Assume that the 11 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. 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