A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 666 babies were born, and 333 of theminterval estimate of the percentage of girls born. Based on the result, does the method appear to be effective?< p < (Round to three decimal places as needed.)n example Get more help -h ty of conceiving a girl. In the study 666 babies were born, and 333 of them were girls. Use the sample data to construct a 99% confidencesult, does the method appear to be effective?4

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 666 babies were born, and 33 interval estimate of the percentage of girls born. Based on the result, does the method appear to be effective?

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 666 babies were born, and 33 interval estimate of the percentage of girls born. Based on the result, does the method appear to be effective?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 666 babies were born, and 333 of them
interval estimate of the percentage of girls born. Based on the result, does the method appear to be effective?
< p < (Round to three decimal places as needed.)
n example Get more help -
h

ty of conceiving a girl. In the study 666 babies were born, and 333 of them were girls. Use the sample data to construct a 99% confidenc
esult, does the method appear to be effective?
4

Expert Solution

Step 1

$g i v e n d a t a, n = 666 x = 333 \hat{p} = \frac{333}{666} = 0.5 C I = 0.99 α = 1 - 0.99 = 0.01 p (Z < Z_{c}) = 1 - α / 2 = 1 - 0.01 / 2 = 1 - 0.005 = 0.9950 p (Z < Z_{c}) = 0.995 Z_{c} = 2.576 [f r o m e x c e l f u n c t i o n c o d e : = N O R M S I N V (0.9950)]$

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