a) Clearly explain how you obtain the Modified Euler's method. i.e. h Yn+1 = Yn + hf(tn + h 2. Yn +f(tn, Yn)) Given y' = t2 - y, y(0) = 1, find correct to four decimal places the value of y(0.1) and y(0.2) by using Modified Euler's method. b) Solve y' = -2t – y in the interval 0 < t < 0.6 by Modified Euler's method taking h = 0.2 given that y(0) = -1 Solve y' = log(t+y) in the time interval 0

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Can I have a detailed, step-by-step explanation for the part (c) of the following question?

Kindly include the relevant reasoning/assumptions made during simplifications & calculations along with them.

Thank you very much!

 

a) Clearly explain how you obtain the Modified Euler's method. i.e.
h
Yn+1 = Yn + hf(t, +
2. Yn +f(tn, Yn))
Given y' = t2 – Y, y(0) = 1, find correct to four decimal places the value of y(0.1) and
y(0.2) by using Modified Euler's method.
b) Solve y
h = 0.2 given that y(0) = -1
-2t – y in the interval 0 < t < 0.6 by Modified Euler's method taking
c Solve y' = log(t+y) in the time interval 0 <t<0.2 by Modified Eulers method taking
h = 0.1 given that y(0) = 1.
Transcribed Image Text:a) Clearly explain how you obtain the Modified Euler's method. i.e. h Yn+1 = Yn + hf(t, + 2. Yn +f(tn, Yn)) Given y' = t2 – Y, y(0) = 1, find correct to four decimal places the value of y(0.1) and y(0.2) by using Modified Euler's method. b) Solve y h = 0.2 given that y(0) = -1 -2t – y in the interval 0 < t < 0.6 by Modified Euler's method taking c Solve y' = log(t+y) in the time interval 0 <t<0.2 by Modified Eulers method taking h = 0.1 given that y(0) = 1.
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