À clay target is shot from a gun with an initial speed u = 55.6 m/s at an angle 0 = 46.4° above the horizontal. In this question take i as a horizontal unit vector and j as a vertical unit vector. The muzzle of the gun is hi = 1.48 m above the ground, this is the height above the ground that the target is launched from. Part 1) Evaluate the initial velocity of the clay target in unit vector notation. Gm/s ū = Part 2) What is the maximum height the clay target reaches above the launch height? h = m above the launch height Part 3) What horizontal distance from the launch point does the clay target hit the ground? m Note: This is just asking for the difference in the x co-ordinates between the position the clay target is fired from and where it reaches the ground.
À clay target is shot from a gun with an initial speed u = 55.6 m/s at an angle 0 = 46.4° above the horizontal. In this question take i as a horizontal unit vector and j as a vertical unit vector. The muzzle of the gun is hi = 1.48 m above the ground, this is the height above the ground that the target is launched from. Part 1) Evaluate the initial velocity of the clay target in unit vector notation. Gm/s ū = Part 2) What is the maximum height the clay target reaches above the launch height? h = m above the launch height Part 3) What horizontal distance from the launch point does the clay target hit the ground? m Note: This is just asking for the difference in the x co-ordinates between the position the clay target is fired from and where it reaches the ground.
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
Transcribed Image Text:A clay target is shot from a gun with an initial speed u =
this question take
above the ground, this is the height above the ground that the target is launched from.
55.6 m/s at an angle 0 = 46.4° above the horizontal. In
as a horizontal unit vector and j as a vertical unit vector. The muzzle of the gun is hų = 1.48 m
Part 1)
Evaluate the initial velocity of the clay target in unit vector notation.
u =
i+
Gm/s
Part 2)
What is the maximum height the clay target reaches above the launch height?
h =
m above the launch height
Part 3)
What horiz
ntal distance from the launch point does the clay target hit the ground?
Note: This is just asking for the difference in the x co-ordinates between the position the clay target is fired from and
where it reaches the ground.
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