A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 168 feet per second from an initial height of 113 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation: h = – 16t + 168t + 113 Find the two points in time when the object is 146 feet above the ground. Round your answers to the nearest hundredth of a second (two decimal places).

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A: Explanation of the answer as follows:

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