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A circular wire loop of radius 14.9 cm carries a current of 2.13 A. It is placed so that the normal to its plane makes an angle of 37.6° with a uniform magnetic field of magnitude 16.8 T. (a) Calculate the magnitude of the magnetic dipole moment of the loop in amperes-square meters. (b) What is the magnitude of the torque acting on the loop?

(a) Number [Input box] Units [Dropdown]
(b) Number [Input box] Units [Dropdown]

Expert Solution

Step 1

Given that

radius (r)=14.9 cm.

current (i)=2.13 Amp.

(a). Magnetic dipole moment

m=iA

m = i(πr²)

m=(2.13Amp)(3.14×0.149m×0.149m)

m=0.148 Amp-m²

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