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A circular sector has a radius 5mm, and angle 31deg. Compute the centroid of the circular sector, Determine the y-coordinate of the centroid of the shaded area. y h/3=htan 30 htan 30="/13 J₂ = h 2asin 30 3(30) z= Za 17 180 Triangular Area A₁ = ½ (2) h A₂ = -πa² 60 60° 60° Centroid Equation Y = ΣΑΤ (ΣΑ Calculation Table PART 360 2 E 643 4,- 12 T-M3 36 y-A 1 X - 15 A 2h √3 - Па 6 παι EA = 6h²-13πa² 6√3 3 > do Аў 2h3 3√3 Za πT - a 2h3 a³ 3√3 - 3 4h³ - 2√3a² {Ay = 1/1613 Y = 4h³ - 2√3a³ Ў 6h2 - 13 πTa² па Area of Circular Sector rein a a 1-20) 4.-1 sin 2a)

A circular sector has a radius 5mm, and angle 31deg. Compute the centroid of the circular sector, Determine the y-coordinate of the centroid of the shaded area. y h/3=htan 30 htan 30="/13 J₂ = h 2asin 30 3(30) z= Za 17 180 Triangular Area A₁ = ½ (2) h A₂ = -πa² 60 60° 60° Centroid Equation Y = ΣΑΤ (ΣΑ Calculation Table PART 360 2 E 643 4,- 12 T-M3 36 y-A 1 X - 15 A 2h √3 - Па 6 παι EA = 6h²-13πa² 6√3 3 > do Аў 2h3 3√3 Za πT - a 2h3 a³ 3√3 - 3 4h³ - 2√3a² {Ay = 1/1613 Y = 4h³ - 2√3a³ Ў 6h2 - 13 πTa² па Area of Circular Sector rein a a 1-20) 4.-1 sin 2a)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A circular sector has a radius 5mm, and angle 31deg. Compute the centroid of the circular sector,
Transcribed Image Text:A circular sector has a radius 5mm, and angle 31deg. Compute the centroid of the circular sector,
Determine the y-coordinate of the centroid of the shaded area. y h/3=htan 30 htan 30="/13 J₂ = h 2asin 30 3(30) z= Za 17 180 Triangular Area A₁ = ½ (2) h A₂ = -πa² 60 60° 60° Centroid Equation Y = ΣΑΤ (ΣΑ Calculation Table PART 360 2 E 643 4,- 12 T-M3 36 y-A 1 X - 15 A 2h √3 - Па 6 παι EA = 6h²-13πa² 6√3 3 > do Аў 2h3 3√3 Za πT - a 2h3 a³ 3√3 - 3 4h³ - 2√3a² {Ay = 1/1613 Y = 4h³ - 2√3a³ Ў 6h2 - 13 πTa² па Area of Circular Sector rein a a 1-20) 4.-1 sin 2a)
Transcribed Image Text:Determine the y-coordinate of the centroid of the shaded area. y h/3=htan 30 htan 30="/13 J₂ = h 2asin 30 3(30) z= Za 17 180 Triangular Area A₁ = ½ (2) h A₂ = -πa² 60 60° 60° Centroid Equation Y = ΣΑΤ (ΣΑ Calculation Table PART 360 2 E 643 4,- 12 T-M3 36 y-A 1 X - 15 A 2h √3 - Па 6 παι EA = 6h²-13πa² 6√3 3 > do Аў 2h3 3√3 Za πT - a 2h3 a³ 3√3 - 3 4h³ - 2√3a² {Ay = 1/1613 Y = 4h³ - 2√3a³ Ў 6h2 - 13 πTa² па Area of Circular Sector rein a a 1-20) 4.-1 sin 2a)
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