Answered: A circular loop of resistance R=2.15 Q… | bartleby

Related questions

Question

A circular loop of resistance R=2.15 and area A=0.08 m² is placed in a uniform magnetic field. From t-0 on, the field start varying with time
according to B(t)=t-+20t+5, where B is in mT and t in seconds. Find the time t (in s) at which the current passing by the loop is 10.9 mA.
R
EXXXX
XXX
XXX X

Expert Solution

Step by step

Solved in 2 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A conductor consists of a circular loop of radius R = 16.0 cm and two long, straight sections as shown in the figure below. The wire lies in the plane of the page and carries a current I = 1.2 A. Find the magnitude of the magnetic field (in μT) at the center of the loop. Round your answer to 2 decimal places.
A 32.7 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 61.3 cm from the wire. T
A magnetic field directed into the page changes with time according to B = 0.037 ot² + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see figure below). xxxxx xxxxx ****** * I xxx 1 19/ x Rx xxxxx х х xxxxxx x xxxxx Bin P₁ (a) When t = 4.20 s and r₂ = 0.020 0 m, what is the magnitude of the electric field at point P₂? N/C (b) When t = 4.20 s and r₂ = 0.020 0 m, what is the direction of the electric field at point P2? O perpendicular to r₂ and counterclockwise O into the page O perpendicular to r₂ and clockwise O out of the page
A circular loop of wire has radius = 0.1 m and current = 44 A. Find the magnetic field strength at the center of the circle. (in T) OA: 2.447x10-4B: 2.765x10-4 OC: 3.124×10-4 OD: 3.530×10-4 OE: 3.989x10-4 OF: 4.508x10-4 OG: 5.094x10-4 OH: 5.756x10-4
The graph shows the relationship between the magnetic field (B in mT) at the center of a solenoid and the current I (in A). If the solenoid is composed of 33 turns, what is its length in cm? Given that μ = 1.26x10-6 T.m/A B(mT) Round your answer to 1 decimal place. Your Answer: 0.045195 Incorrect The answer is 46.2 ± 5%. Y= 0.092 X + 0.2 I(A)
You have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 x 10-5 T). If your solenoid has 400 turns and is 28 cm long, determine the current you must use in order to obtain a magnetic field of the desired magnitude. mA
Item 12 ▼ Part A Find the radius of an electron's orbit when it moves perpendicular to a magnetic field of 0.66 T with a speed of 6.25×105 m/s. Express your answer using two significant figures. V—| ΑΣΦ T = Submit Request Answer ? μm
A solenoid has 15 turns per centimeter. What current will produce a magnetic field of 1.6×10−21.6×10−2 T within the solenoid? The required current is ________A.
In 10.0 seconds a total charge of 285 C flows through a wire. If the wire is inside of a 31.0 mT perpendicular magnetic field it experiences a magnetic force of 6.00 x 102 N. 20. The length of the wire that is inside of the magnetic field is a.bc x 10d m. The values of a, b, c and dare and (Record your four-digit answer in the numerical-response section below.) Your answer:
A magnetic field directed into the page changes with time according to B = 0.035 or? + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see figure below). x x x x * * x X x x x xx x X X x x X x x x x x R x * x x x x X x x x x x Bin (a) When := 4.70 s and r = 0.020 0 m, what is the magnitude of the electric field at point P,? N/C (b) When = 4.70 s and r,= 0.020 0 m, what is the direction of the electric field at point P,? O perpendicular to r2 and clockwise O perpendicular to r, and counterclockwise into the page O out of the page
A magnetic field directed into the page changes with time according to B = 0.031 ot² + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see figure below). xxxx vPg xxx xxx xxxx x Rx Bin P₁ (a) When t = 4.80 s and r₂ = 0.020 0 m, what is the magnitude of the electric field at point P₂? 0.00030 X Your response is off by a multiple of ten. N/C (b) When t = 4.80 s and r₂ = 0.020 0 m, what is the direction of the electric field at point P₂? perpendicular to r₂ and counterclockwise O into the page O out of the page. O perpendicular to ₂ and clockwise