A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. F1 = 5 N applied at the outer edge of the disc. F2 = 3.8 N applied at a distance of 0.22 from the center of the disc. What is the net torque on the disc?
A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. F1 = 5 N applied at the outer edge of the disc. F2 = 3.8 N applied at a distance of 0.22 from the center of the disc. What is the net torque on the disc?
College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter8: Rotational Equilibrium And Rotational Dynamics
Section: Chapter Questions
Problem 11WUE
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A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction.
F1 = 5 N applied at the outer edge of the disc.
F2 = 3.8 N applied at a distance of 0.22 from the center of the disc.
What is the net torque on the disc?
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