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A circular cylinder of radius 1 and the parabolic cylinder x = 2y? – 1 2 =

A circular cylinder of radius 1 and the parabolic cylinder x = 2y? – 1 2 =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
A circular cylinder of radius 1 and the parabolic cylinder z = 2y? – 1
Transcribed Image Text:A circular cylinder of radius 1 and the parabolic cylinder z = 2y? – 1
intersect as shown in Which vector function r(t) x(t) i+ y(t)j+ z(t) k has the curve of intersection as its graph if x(0) = 0? 1. r(t) (sin t) i+ (cost) j+(1– cos 2t) k 2. r(t) = (sin t)i+(cost) j+(cos 2t) k 3. r(t) = (cost) i+(sin t) j+ (cos 2t) k 4. r(t) = (sin t) i+(cos t) j+(cos 2t – 1) k 5. r(t) — (сos t)і+(sint)j+ (1— сos 2t) k 6. r(t) = (cos t) i+(sin t) j+(cos 2t – 1) k
Transcribed Image Text:intersect as shown in Which vector function r(t) x(t) i+ y(t)j+ z(t) k has the curve of intersection as its graph if x(0) = 0? 1. r(t) (sin t) i+ (cost) j+(1– cos 2t) k 2. r(t) = (sin t)i+(cost) j+(cos 2t) k 3. r(t) = (cost) i+(sin t) j+ (cos 2t) k 4. r(t) = (sin t) i+(cos t) j+(cos 2t – 1) k 5. r(t) — (сos t)і+(sint)j+ (1— сos 2t) k 6. r(t) = (cos t) i+(sin t) j+(cos 2t – 1) k
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