A circular curve has the following data: Azimuth of back tangent = 205° Azimuth of forward tangent = 262° Middle ordinate = 5.80m Find the length of the tangent c. 22.66 m d. 24.88 m a. 25.99 m b. 23.77 m

A circular curve has the following data: Azimuth of back tangent = 205° Azimuth of forward tangent = 262° Middle ordinate = 5.80m Find the length of the tangent c. 22.66 m d. 24.88 m a. 25.99 m b. 23.77 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: PROBLEM 3 Given: (Use Arc Basis) 11 = 18⁰, 12 = 25⁰ T₁ = 100 m t₁ = 32 m Station PT at 12+628 PC…

Q: The long chord from the P.C to the P.T of a compound curve is 270.94 meters long and the angles its…

Q: B calculated as follows : E 4, R .R 28, 26, 28,

Q: Example 3: Try This In Your Own......... The tangent distance of a simple curve is 94.963m and its…

Q: Two lines XV and YV intersect at an inaccessible point V. Two points A and B are selected on lines…

A: *Multiple Sub- parts*As per our company guidelines, we are supposed to answer only the first 3…

Q: = A highway survey PI falls in a pond, so a cut off line AB= 275.21 ft is run between the tangents.…

A: Degree of curve = 4o30'Angle A = 16o 28'Angle B = 22o16'AB= 275.21 ft station of A = 54 +…

Q: Calculate all required data for the following vertical curve. Curve 2 is to be staked at the even 20…

A: PVCSTATION=PVISTA-L2PVCsta=6500-2002=6+400PVCELV=PVIELV-g1L2PVCelv=170-0.075×2002PVCelv=162.5mEquati…

Q: The length of a simple curve having a degree of curve of 5° is equal to 130 m. If the stationing of…

A: NOTE : Since you have posted a question with multiple sub-parts, we will solve the first three…

Q: With the same problem use the following formula and sketch the curve accurately. Curve length(L) =…

A: Given:- The angle of intersection of the curve = 45°30' The radius of the curve = 198.17 m The…

Q: Two roads AB and BC intersect at a chainage 184+65. These are intersected by a line PQ and the…

Q: Calculate all required data for the following vertical curve. Curve 1 is to be staked at the even 20…

A: PVCSTATION=PVISTA-L2PVCsta=9280-3002=9+130PVCELV=PVIELV-g1L2PVCelv=150+0.1125×3002PVCelv=161.25mPVTS…

Q: SITUATION X: A simple curve has a degree of 6 and the tangent intersects at 42 degrees. 17. What is…

Q: Same situation as provided in the question in the image shared. Suppose the spiral curve is…

A: Given data: Length of the spiral curve=230 ft Normal crown rate = 2.5% Design Speed, V = 50 mph…

Q: Find the length of the tangents

Q: he figure shown AB = 103.20m with A at Station 10+158.93. The angle VAC is 15°21' and le VBC is…

Q: SITUATION 17: AB and BC are tangents of a simple curve. AB is due north and BC is N50°E. Degree of…

A: From the Above ∆of the curve = 50° Degree of the curve = 4 ° For 20 m chain Degree D = 1146/R R=…

Q: Listen Spiral curves are characterized by which of the following? 01 Constant radius 21 Constantly…

A: Spiral curve These curves are widely used in highways or rail tracks.

Q: A reverse curve connects two converging tangents that intersect at an angle of 30°. The distance of…

A: Reverse Curve: The road surface planning mandates that the road connecting the two locations take…

Q: A highway survey PI falls in a pond, so a cut off line AB= 275.21 ft is run between the tangents. In…

A: Degree of curve = 4°30' Angle A = 16°28' Angle B = 22°16' Station of A =54 + 92.30

Q: A compound curve has the following data: Stationing P.I. 50+ 120.5 I₁ = 28 º 1₂ = 31 ° D₁ = 3⁰ D₂ =…

A: Appreciate if there is detailed work with explanation and finds you helpful for ease of…

Q: Plot the traverse listed below: Line AzimuthS АВ 225 degrees ВС 225 degrees CD 301 degrees DE 301…

Q: A highway intersection of 50° is to be connected by a 6° simple curve and 90 m long spiral curve on…

A: Appreciate if there is detailed work with explanation and finds you helpful for ease of…

Q: The figure below shows A simple horizontal curve of 5° curvature. Using the values in the figure.…

A: Length of Curve Station of PI Station of PT

Q: Given the following data in a sample D = 5°, Sta PC = 1+234.56. Azimuth of the back and forward…

A: Given: D = 5°, Station PC = 1+234.56m Back tangent= 230° Forward tangent=135°15' Required to find:…

Q: Q/ on the (+ profile) vertical vertical curve. The table below represents the reading of the ruler…

A: Station back sight Intermediate sight Fore sight height of instrument elevation Remark 0+00 4.365…

Q: With the same problem, use the following formula. R = 191.07m , T = 62.082 , Lc = 118.088m , E =…

A: ###Determination for simple circular curve of various terms ###

Q: A highway survey PI falls in a pond, so a cut off line A the tangents. In the triangle formed by…

Q: 3. A horizantal curve of R=500 m has a point of curvature PC : Km: 0+500, elevation: +50.00.…

A: Horizontal curve radius, R = 500 m Point of curvature, PC = 0+ 500 km Elevation = + 50.00 km…

Q: mine the internal oment at point B

A: Solution: Considering the diagram:

Q: Two tangents AB and BC meet in an inaccessible point B and are to be connected by a simple curve of…

Q: Problem 1. A simple curve have tangents AB and BC intersecting at a common point B. AB has an…

A: Given:- I=Angle of intersection=230o-180oDegree of curve=4oRadius=17194=429.5 m

Q: (a): What are different types of curves? Support your answer with neat and clean sketches. (b):…

A: Regular bends designed to induce a steady change of direction are known as road curves.

Q: Compute the length of a horizontal circular curve, if you know its external distance equal E=49.36 m…

A: External distance(E)=49.36 m, Radius of the curve(R)=667.04 m.

Q: A vertical sag parabolic curve has a length of 450m. Its back tangent has a slope of -3.20%. The…

Q: From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths…

Q: 1. The common tangent AB of a compound curve makes an angle with the tangents of the compound curve…

Q: iven: R=310m PI chainage = 905.280m BC station = 639.280m EC chainage = 1138.491m Determine : a.…

A: Step 1

Q: 39. The external distance of a simple curve is 10.20m, and has a central angle of 36° 40'. Find the…

Q: Fundamentals of Surveying: Please show your solution. 3.) A simple curve has 337m radius and 64°…

A: Given :Simple Circular Curves Radius =337m…

Q: Two Straight lines AB and BC intersect at chainage 7827 m, the deflection angle being (49)ᴼ . It is…

A: As we know formula of design of curve Let us take 30m Chain length R= 1720/D° = 1720/4° R =…

Q: BEARING OF PC-V = N 60° E BEARING OF V-PT S 70° E DEGREE OF CURVE CO) STATION Ve 12 t 234.50 %3D

Q: If the radius of curve is 380m, what is its degree designation on 20m arc? 1. 0.0526 2. 0.00526 3.…

Q: ord, find the radius of the second curve in meters.

Concept explainers

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.

Question

100%

2. A circular curve has the following data:
Azimuth of back tangent = 205°
Azimuth of forward tangent = 262°
Middle ordinate = 5.80m
Find the length of the tangent
a. 25.99 m
b. 23.77 m
c. 22.66 m
d. 24.88 m

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1: Answer

VIEW

Step 2:

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

1. 2. The length of the curve of a simple curve having a degree of curve 4 degrees is equal to 210m. a. Compute the middle ordinate of the curve. b. Compute the external distance of the curve. c. Compute the area of the fillet of the curve.
List the given, required and box the final answer.
Calculate with sketch the elements and the main static PC, PT) for a simple circular curve if its radius R = 350m, degree of curvature D = 57' 13' and Sta. PI = 11+75
Show complete solution and provide necessary illustration/s.
Problem 2. Given are the following coordinates of stations of a simple curve: Northings Eastings Station PC PI PT 20,122.84 20.143.97 20131.03 Calculate the elements of the curve. Calculate also the deflection angles and the corresponding length of chord for every full station if PC is at 2 + 004.91. 19.791.20 19,836.52 19884.82
Topic: Elements of a Horizontal Simple Circular Curve Question: A simple curve has an l= 38° 12' and D= 70 00'. Calculate the equivalent external distance and middle ordinate of the curve.
COMPOUND CURVE Station PT of a compound curve is at 15 + 480, I, = 30°, I2 = 36°, D1 = 4°, and D2 = 5°. What is the stationing of PCC? Use arc basis. a. 15 + 319.63 b. 15 + 336.14 C. 15 + 325.28 d. 15 + 342.50
Topic: Surveying (8)
Two roads AB and BC intersect at a chainage 184+65. These are intersected by a line PQ and the angles APQ and PQC are 112° and 102° respectively. The radius of the first arc of the curve is 330m and that of the second arc is 540m. Calculate the chainages of the first and the second tangent points P.C R₂ 2 P.T 185+87.15, 172+18.67 O 170+88.19, 182+14.97 O 176+48.69, 172+18.67 O 185+87.19, 152+14.97 O 190+84.32, 177+12.34 O
The deflection angle and the length of the middle ordinate of a simple curve is 75 meters and 40 degrees respectively, what is the least measurement of the degree of curve? 1.20 O 1.30 O 1.15 3.25
SITUATION 15: AB and BC are tangents of a simple curve. AB is due north and BC is N50°E. Degree of simple curve is 4° and PT is at station 20 + 130. 42. Determine the external distance. c. 29.62 m d. 30.23 m c. 14.66 m d. 10.4 m
Question 1 A highway survey PI falls in a pond, so a cut off line AB = 275.21 ft is run between the tangents. In the triangle formed by points A, B, and PI, the angle at A = 16°28' and at B = 22°16'. The station of A is 54 + 92.30. Calculate and tabulate curve notes to run, by deflection angles and incremental chords, a 4°30' (arc definition) circular curve at full-station increments to connect the tangents.