A circular conductor encloses a uniform magnetic field that is perpendicular to the page (not shown), pointing inward and increasing. The magnetic field outside the circular loop is zero. Suppose the changing magnetic flux induces a 7.5-V emf in the conductor and the conductor's resistance is 1.0 0. Imagine connecting two voltmeters to the conductor (see figure below). The clockwise distance from A to B is one-fourth the circumference, Because the resistance of a wire is proportional to its length, this portion of the loop has resistance R1 = 0.25 0. Likewise, the clockwise distance from B to A is three-fourths the circumference, so this portion's resistance is R2 - 0.75 0. It may seem incredible, but what a voltmeter measures depends on its placement; it can be shown that V- V-E. Find the voltage measured by both meters. Hint: Kirchhoff's loop rule (and other rules) may be applied to a loop that does not enclose the changing magnetic flux. (Indicate the direction with the sign of your answer.) Path I R2- 0.75 2 (v R 0.25 0 90.0 Path 2

A circular conductor encloses a uniform magnetic field that is perpendicular to the page (not shown), pointing inward and increasing. The magnetic field outside the circular loop is zero. Suppose the changing magnetic flux induces a 7.5-V emf in the conductor and the conductor's resistance is 1.0 0. Imagine connecting two voltmeters to the conductor (see figure below). The clockwise distance from A to B is one-fourth the circumference, Because the resistance of a wire is proportional to its length, this portion of the loop has resistance R1 = 0.25 0. Likewise, the clockwise distance from B to A is three-fourths the circumference, so this portion's resistance is R2 - 0.75 0. It may seem incredible, but what a voltmeter measures depends on its placement; it can be shown that V- V-E. Find the voltage measured by both meters. Hint: Kirchhoff's loop rule (and other rules) may be applied to a loop that does not enclose the changing magnetic flux. (Indicate the direction with the sign of your answer.) Path I R2- 0.75 2 (v R 0.25 0 90.0 Path 2