A circular aluminum alloy [E = 70 GPa; α = 22.5 × 10–6/°C; ν = 0.33] pipe has an outside diameter of 185 mm, a wall thickness of 5 mm, and a length of 5.0 m. The pipe supports a compressive load of 675 kN. After the temperature of the pipe drops 39°C, determine: (a) the axial deformation of the pipe. (b) the change in diameter of the pipe
A circular aluminum alloy [E = 70 GPa; α = 22.5 × 10–6/°C; ν = 0.33] pipe has an outside diameter of 185 mm, a wall thickness of 5 mm, and a length of 5.0 m. The pipe supports a compressive load of 675 kN. After the temperature of the pipe drops 39°C, determine: (a) the axial deformation of the pipe. (b) the change in diameter of the pipe
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
A circular aluminum alloy [E = 70 GPa; α = 22.5 × 10–6/°C; ν = 0.33] pipe has an outside diameter of 185 mm, a wall thickness of 5 mm, and a length of 5.0 m. The pipe supports a compressive load of 675 kN. After the temperature of the pipe drops 39°C, determine:
(a) the axial deformation of the pipe.
(b) the change in diameter of the pipe.
![A circular aluminum alloy [E = 70 GPa; a = 22.5 × 10-6/°C; v = 0.33] pipe has an outside diameter of 185 mm, a wall thickness of 5 mm,
and a length of 5.0 m. The pipe supports a compressive load of 675 kN. After the temperature of the pipe drops 39°C, determine:
(a) the axial deformation of the pipe.
(b) the change in diameter of the pipe.
Answer:
(a) d = i
mm
AD= i
mm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0340ab0c-e54f-482a-bc54-4a3b868cdaba%2Fe5396eb1-b79c-475c-a82e-796be3963acd%2Fqhqt1me_processed.png&w=3840&q=75)
Transcribed Image Text:A circular aluminum alloy [E = 70 GPa; a = 22.5 × 10-6/°C; v = 0.33] pipe has an outside diameter of 185 mm, a wall thickness of 5 mm,
and a length of 5.0 m. The pipe supports a compressive load of 675 kN. After the temperature of the pipe drops 39°C, determine:
(a) the axial deformation of the pipe.
(b) the change in diameter of the pipe.
Answer:
(a) d = i
mm
AD= i
mm
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