A circle has center (5, -4) and radius 8. Which gives the equation for the circle? O A. (K + 5)2 + (y – 4)² = 8 O B. (x- 5)2 + (y + 4)2 = 8 O C. * + 5)2 + v – 4)2 = 64 O D. (x- 5)2 + (v + 4)² = 64

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Question:**

Which angles are congruent to ∠3?

**Diagram Explanation:**

The diagram shows two parallel lines intersected by a transversal line. The intersection creates eight numbered angles. Specifically, angles 1 through 4 are formed at the intersection of the transversal with the first parallel line, and angles 5 through 8 are formed at the intersection with the second parallel line.

**Answer Choices:**

A. ∠2

B. ∠2, ∠6

C. ∠6

D. ∠2, ∠6, ∠7

**Explanation:**

To find which angles are congruent to ∠3, we apply the properties of parallel lines and transversals. Congruent angles could include corresponding angles, alternate interior angles, or vertical angles.
Transcribed Image Text:**Question:** Which angles are congruent to ∠3? **Diagram Explanation:** The diagram shows two parallel lines intersected by a transversal line. The intersection creates eight numbered angles. Specifically, angles 1 through 4 are formed at the intersection of the transversal with the first parallel line, and angles 5 through 8 are formed at the intersection with the second parallel line. **Answer Choices:** A. ∠2 B. ∠2, ∠6 C. ∠6 D. ∠2, ∠6, ∠7 **Explanation:** To find which angles are congruent to ∠3, we apply the properties of parallel lines and transversals. Congruent angles could include corresponding angles, alternate interior angles, or vertical angles.
**Circle Equation Identification Exercise**

**Question:**
A circle has center (5, –4) and radius 8. Which gives the equation for the circle?

**Options:**
- A. \((x + 5)^2 + (y - 4)^2 = 8\)
- B. \((x - 5)^2 + (y + 4)^2 = 8\)
- C. \((x + 5)^2 + (y - 4)^2 = 64\)
- D. \((x - 5)^2 + (y + 4)^2 = 64\)

**Explanation:**
The standard form of the equation of a circle with center \((h, k)\) and radius \(r\) is:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
Given the center \((5, -4)\), we substitute \(h = 5\) and \(k = -4\). The radius is 8, hence \(r^2 = 64\). 

Substituting these values into the standard form equation, we get:
\[
(x - 5)^2 + (y + 4)^2 = 64
\]

Therefore, the correct answer is: **Option D: \((x - 5)^2 + (y + 4)^2 = 64\)**.
Transcribed Image Text:**Circle Equation Identification Exercise** **Question:** A circle has center (5, –4) and radius 8. Which gives the equation for the circle? **Options:** - A. \((x + 5)^2 + (y - 4)^2 = 8\) - B. \((x - 5)^2 + (y + 4)^2 = 8\) - C. \((x + 5)^2 + (y - 4)^2 = 64\) - D. \((x - 5)^2 + (y + 4)^2 = 64\) **Explanation:** The standard form of the equation of a circle with center \((h, k)\) and radius \(r\) is: \[ (x - h)^2 + (y - k)^2 = r^2 \] Given the center \((5, -4)\), we substitute \(h = 5\) and \(k = -4\). The radius is 8, hence \(r^2 = 64\). Substituting these values into the standard form equation, we get: \[ (x - 5)^2 + (y + 4)^2 = 64 \] Therefore, the correct answer is: **Option D: \((x - 5)^2 + (y + 4)^2 = 64\)**.
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