e A CI is desired for the true average stray-load loss μ (watts) for a certain type of induction motor when the line current is held at10 amps for a speed of 1500 rpm. Assume that stray-load loss is normally distributed with o = 2.9. (Round your answers to twodecimal places.)(a) Compute a 95% CI for μ when n = 25 and x = 52.9.54.04)51.76(b) Compute a 95% CI for μ when n = 100 and x = 52.9.53.47)52.3352.15I(c) Compute a 99% CI for μ when n = 100 and x = 52.9.53.65)₁52.51IwattsIwatts(d) Compute an 82% CI for u when n = 100 and x = 52.9.53.29)₁Xwattswatts(e) How large must n be if the width of the 99% interval for u is to be 1.0? (Round your answer up to the nearest wholenumber.)n = 56

We need to determine the value of n if the width of the 99% interval for is 1.0.(e) To determine the sample size required for a 99% CI with a width of 1.0, we need to find the value of n in the formula:The value of can be determined using Excel function given below:=NORM.S.INV(0.005)The value of is 2.58.Given that the width of the CI is 1.0, we have:Simplifying and solving for n:Rounding up to the nearest whole number, the required sample size is 224.Therefore, the sample size must be at least 224 to achieve a 99% CI with a width of 1.0.e) The sample size must be at least 224 to achieve a 99% CI with a width of 1.0.