A child starts at one corner of a cubical jungle gym in a playground and climbs up to the diagonally opposite corner. The original corner is the coordinate origin, and the x, y and z axes are oriented along the jungle gym edges. The length of each side is 2 m. The child's displacement is:
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- Vector V1 is 5.0 units long and points along the negative x-axis. Vector V2 is 10.0 units long and points at an angle of 30.0 degrees above the positive x-axis. (a) Find the x and y components of the vector sum V2 + V1 and then determine the magnitude and direction of the vector sum V2+V1. (b) Sketch the vector sum V2+V1 on a grid.A hiker walks 2.5 miles in a direction 65° West of North, then 3.5 miles in a direction 40° South of West, then 1.5 miles due South. What must be the vector displacement of the hiker during the fourth part of the trip in order for the resultant to be 5.5 miles due West for the entire trip? Drawing a vector diagram or drawing individual vectors will help.A vector has the components Ax=22mAx=22m and Ay=16mAy=16m. a) What is the magnitude of this vector? Express your answer to two significant figures and include appropriate units. b) What angle does this vector make with the positive x axis? Express your answer to two significant figures and include appropriate units.
- For the given vectors V₁ and V2, determine V₁ + V2, V₁ + V2, V₁-V2, V1X V2, V₂ X V₁, and V₁ V₂. Consider the vectors to be nondimensional. V₂ = 11 Answers: V₁ + V₂ = V₁ + V₂ = V₁-V₂= V₁x V₂ = V₂X V₁ = V₁ V₂ = 69° i i i i i i 4 3 V₁ = 13 i+ i i+ i+ i i i+ i j+ i j+ i i k k k kSydney, Tayler and I go out for a short walk together. We first walked 10 meters 34° South of East, then 20 meters due South, and then 15 meters 42° South of West. We want to find the overall resultant vector of our total travels.A treasure hunter following a map walks 11 meters south, 9 meters east, 2 meters north, and 4 meters west. Find the (x,y) coordinates of the treasure hunter’s displacement, and the magnitude of the displacement vector.
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