**Title:** Calculating the Diameter of a Submerged Styrofoam Ball**Description:**A child playing in a swimming pool realizes that it is easy to push a small inflated ball under the surface of the water whereas a large ball requires a lot of force. The child happens to have a styrofoam ball (the shape of the ball will not distort when it is forced under the surface), which he forces under the surface of the water. If the child needs to supply 5.00 x 10² N to totally submerge the ball, calculate the diameter \( d \) of the ball. The density of water is \( \rho_w = 1.000 \times 10^3 \, \text{kg/m}^3 \), the density of styrofoam is \( \rho_{\text{foam}} = 95.0 \, \text{kg/m}^3 \), and the acceleration due to gravity is \( g = 9.81 \, \text{m/s}^2 \).**Equation:**\[ d = \sqrt[³]{\frac{6 \times F}{\pi \times (\rho_w \times g - \rho_{\text{foam}} \times g)}} \](Make sure to solve this equation using the given values to find the diameter \( d \) in meters.)**User Input Box:**A text field is provided for the user to input their calculated value of \( d \), with a button labeled "TOOLS" next to it, and the option to multiply by \( x10^x \) for scientific notation.**Note:** This activity involves understanding concepts such as buoyancy, forces, and density, and requires application of formulas related to physics and mathematics.

Name: **Title:** Calculating the Diameter of a Submerged Styrofoam Ball**De
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Description: **Title:** Calculating the Diameter of a Submerged Styrofoam Ball**Description:**A child playing in a swimming pool realizes that it is easy to push a small inflated ball under the surface of the water whereas a large ball requires a lot of force. T

Given: F0=5.00×102Nρw=103kg/m3ρfoam=95.0 kg/m3 So, the ball will be fully immersed when its…

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Physics

A child playing in a swimming pool realizes that it is easy to push a small inflated ball under the surface of the water whereas a large ball requires a lot of force. The child happens to have a styrofoam ball (the shape of the ball will not distort when it is forced under the surface), which he forces under the surface of the water. If the child needs to supply 5.00 × 10² N to totally submerge the ball, calculate the diameter d of the ball. The density of water is pw = 1.000 × 10³ kg/m³, the density of 95.0 kg/m', and the acceleration due to gravity is g = 9.81 m/s². styrofoam is Pfoam =

A child playing in a swimming pool realizes that it is easy to push a small inflated ball under the surface of the water whereas a large ball requires a lot of force. The child happens to have a styrofoam ball (the shape of the ball will not distort when it is forced under the surface), which he forces under the surface of the water. If the child needs to supply 5.00 × 10² N to totally submerge the ball, calculate the diameter d of the ball. The density of water is pw = 1.000 × 10³ kg/m³, the density of 95.0 kg/m', and the acceleration due to gravity is g = 9.81 m/s². styrofoam is Pfoam =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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