A child is sitting on the outer edge of a merry-go-round that is 18 m in diameter. If makes 5.4 rev/min, what is the velocity of the child in m/s? the merry-go-round 3.6 m/s 10.2 m/s 0.8 m/s 5.1 m/s

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Chapter7: Rotational Motion And Gravitation
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### Circular Motion Problem

**Question:**
A child is sitting on the outer edge of a merry-go-round that is 18 meters in diameter. If the merry-go-round makes 5.4 revolutions per minute, what is the velocity of the child in meters per second (m/s)?

**Answer Choices:**
- ⬤ 3.6 m/s
- ⬤ 10.2 m/s
- ⬤ 0.8 m/s
- ⬤ 5.1 m/s

### Explanation
To solve this problem, we need to determine the linear velocity (v) of the child sitting on the edge of the merry-go-round.

1. **Calculate the Radius:**
   The diameter of the merry-go-round is given as 18 meters. The radius (r) is half of the diameter.
   \[
   r = \frac{d}{2} = \frac{18 \text{ m}}{2} = 9 \text{ m}
   \]

2. **Convert Revolutions per Minute to Revolutions per Second:**
   The merry-go-round makes 5.4 revolutions per minute. We need to convert this to revolutions per second (rps).
   \[
   \text{Revolutions per second} = \frac{\text{Revolutions per minute}}{60} = \frac{5.4}{60} = 0.09 \text{ rps}
   \]

3. **Calculate the Circumference:**
   The circumference (C) of a circle is given by:
   \[
   C = 2 \pi r = 2 \cdot \pi \cdot 9 \text{ m} = 18 \pi \text{ m}
   \]

4. **Determine the Linear Velocity:**
   The linear velocity (v) is calculated by multiplying the circumference by the number of revolutions per second (rps):
   \[
   v = C \cdot \text{rps} = 18 \pi \text{ m} \cdot 0.09 \text{ rps} = 1.62 \pi \text{ m/s} \approx 5.1 \text{ m/s}
   \]

**Correct Answer:**
- ⬤ 5.1 m/s
Transcribed Image Text:### Circular Motion Problem **Question:** A child is sitting on the outer edge of a merry-go-round that is 18 meters in diameter. If the merry-go-round makes 5.4 revolutions per minute, what is the velocity of the child in meters per second (m/s)? **Answer Choices:** - ⬤ 3.6 m/s - ⬤ 10.2 m/s - ⬤ 0.8 m/s - ⬤ 5.1 m/s ### Explanation To solve this problem, we need to determine the linear velocity (v) of the child sitting on the edge of the merry-go-round. 1. **Calculate the Radius:** The diameter of the merry-go-round is given as 18 meters. The radius (r) is half of the diameter. \[ r = \frac{d}{2} = \frac{18 \text{ m}}{2} = 9 \text{ m} \] 2. **Convert Revolutions per Minute to Revolutions per Second:** The merry-go-round makes 5.4 revolutions per minute. We need to convert this to revolutions per second (rps). \[ \text{Revolutions per second} = \frac{\text{Revolutions per minute}}{60} = \frac{5.4}{60} = 0.09 \text{ rps} \] 3. **Calculate the Circumference:** The circumference (C) of a circle is given by: \[ C = 2 \pi r = 2 \cdot \pi \cdot 9 \text{ m} = 18 \pi \text{ m} \] 4. **Determine the Linear Velocity:** The linear velocity (v) is calculated by multiplying the circumference by the number of revolutions per second (rps): \[ v = C \cdot \text{rps} = 18 \pi \text{ m} \cdot 0.09 \text{ rps} = 1.62 \pi \text{ m/s} \approx 5.1 \text{ m/s} \] **Correct Answer:** - ⬤ 5.1 m/s
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