A chemistry student weighs out 0.0176 g of formic acid (HCHO,) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1300M NAOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits.

Q: An analytical chemist weighs out 0.143 g of an unknown monoprotic acid into a 250 mL volumetric…

A: The point in the titration curve, where the moles of acid and the moles of the base are equal in…

Q: A chemist prepares a solution of aluminum sulfite (Al, (SO,)) by measuring out 57.0 umol of aluminum…

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Q: A chemistry student weighs out 0.0484 g of hypochlorous acid (HCIO) into a 250. ml. volumetric flask…

A:

Q: A chemist must prepare 750. mL of 1.00 M aqueous nickel(II) chloride (NiCl₂) working solution. He'll…

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Q: A chemist must prepare 625.mL of 149.μM aqueous magnesium fluoride MgF2 working solution. He'll…

A: Dilution is the solution obtained by adding more solvent in the stock (more concentrated) solution.…

Q: A chemistry student weighs out 0.0755 g of lactic acid (HC₂H₂O₂) into a 250. mL volumetric flask and…

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Q: A chemist prepares a solution of copper(II) sulfate (CuSO4) by measuring out 69.2g of copper(II)…

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Q: chemist prepares a solution of sodium carbonate (Na, CO, by weighing out 62.1 g of sodium carbonate…

A: We have given that Mass of Na2CO3 = 62.1 grams Volume of volumetric flask = 300mL  i.e.…

Q: A chemist must dilute 0.09 L of 2.98 M aqueous sodium nitrate (NaNO3) solution until the…

A: Initial volume = 0.09 L  Initial Molarity = 2.98 M  Final Molarity = 2.00 M  Final volume = ?

Q: A chemist prepares a solution of copper(II) fluoride (CuF2) by measuring out 0.058g of copper(II)…

A: Given,Mass of CuF2 = 0.058 gVolume of solution = 300 mL = 0.3 L   (1 mL = 0.001 L)Moles of CuF2 can…

Q: A chemist must prepare 300.mL of 2.00M aqueous silver perchlorate AgClO4 working solution. He'll…

A: Dilution equation:                                                  M1V1 = M2V2 where, M1 = Initial…

Q: A chemist prepares a solution of potassium iodide (KI) by measuring out 2.4 x 10² μmol of potassium…

A: we have to calculate the concentration of KI solution

Q: A chemist prepares a solution of sodium nitrate (NANO,) by weighing out 20.56 g of sodium nitrate…

A: Given mass of NaNO3 = 20.56 g  Volume of solution = 50 mL  Concentration in g/L

Q: A chemist prepares a solution of copper(II) sulfate (CuSO4) by measuring out 15. g of copper(II)…

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Q: A chemist prepares a solution of calcium sulfate (CaSO,) by weighing out 0.293 g of calcium sulfate…

A: Mass of CaSO4 taken = 0.293 g Volume of the CaSO4 solution prepared = 400 ml = 0.4 L

Q: A chemist prepares a solution of barium chloride (BaCl₂) by measuring out 26.5 μmol of barium…

A: Given  BaCl2 measurement in a volumetric flask  is Number of moles = 26. 5 numol Volume   = 300.mL…

Q: A chemistry student weighs out 0.0665 g of sulfurous acid (H,So,), a diprotic acid, into a 250. mL…

A: The detailed solution of your question given below-- Since, we know that if number of moles constant…

Q: You have a stock solution of HCI that is 37.4 % HCl by mass and has a density of 1.20 g/mL. What…

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Q: chemist prepares a solution of silver(I) nitrate AgNO3 by measuring out 6.4102 x 10^2 μmol of…

A: Molarity is defined as total number of solute dissolve in one litre of solution Molarity…

Q: A chemist prepares a solution of silver nitrate (AgNO3) by measuring out 0.79 kg of silver nitrate…

A:

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.