A chemist wants to determine the concentration of an unknown HCl solution. She prepares a base standard solution by dissolving 33.45 g of magnesium hydroxide, Mg(OH)2 in 500.0 mL of water. She took a 35.00 mL sample of the unknown acid and titrated it with the known base. The data below shows her volume measurements for her base standard. Trial 1: V1 = 45.00 mL V2 = 3.51 mL

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A chemist wants to determine the concentration of an unknown HCI solution. She
prepares a base standard solution by dissolving 33.45 g of magnesium hydroxide,
Mg(OH)2 in 500.0 mL of water.
She took a 35.00 mL sample of the unknown acid and titrated it with the known
base. The data below shows her volume measurements for her base standard.
Trial 1: V1 = 45.00 mL V2 = 3.51 mL
Trial 2: V2 = 50.00 mL V2 = 8.48 mL
Trial 3: V3 = 50.00 mL V2 = 8.53 mL
%3D
Transcribed Image Text:A chemist wants to determine the concentration of an unknown HCI solution. She prepares a base standard solution by dissolving 33.45 g of magnesium hydroxide, Mg(OH)2 in 500.0 mL of water. She took a 35.00 mL sample of the unknown acid and titrated it with the known base. The data below shows her volume measurements for her base standard. Trial 1: V1 = 45.00 mL V2 = 3.51 mL Trial 2: V2 = 50.00 mL V2 = 8.48 mL Trial 3: V3 = 50.00 mL V2 = 8.53 mL %3D
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