A chemist prepares a solution of vanadium III bromide   VBr3   by measuring out 0.75g of VBr3 into a 250.mL volumetric flask and filling to the mark with distilled water.   Calculate the molarity of Br− anions in the chemist's solution.   Be sure your answer is rounded to the correct number of significant digits. molL

Q: A student wants to make a 0.600 M aqueous solution of barium sulfate, BaSO4, and has a bottle…

A: final volume = 85.7 mL

Q: A chemist prepares a solution of iron III bromide FeBr3 by measuring out 3.00g of FeBr3…

A: Answer : mole  = mass / molecular weight molarity  = mole * 1000/ volume  (ml) molecular weight of…

Q: A chemist prepares a solution of vanadium III chloride VCl3 by measuring out 0.90g of…

A:

Q: Suppose 3.17g of lead(II) acetate is dissolved in 300.mL of a 0.20 M aqueous solution of ammonium…

A: Given, Mass of lead (II) acetate = 3.17 g Volume of ammonium sulfate = 300.0 mL Molarity of ammonium…

Q: The forensic technician at a crime scene has just prepared a luminol stock solution by adding 17.0 g…

A: To determine the molarity (M) of a solution, you can use the formula:M In this case, you're given…

Q: A chemist prepares a solution of iron III  bromide    FeBr3    by measuring out  0.22g  of…

A: To solve this problem we have to calculate the Molarity of the given solution .Since we know that…

Q: Suppose 3.32 g of nickel(II) iodide is dissolved in 200. mL of a 0.30 M aqueous solution of…

A: The equation is,

Q: Suppose 2.90 g of ammonium bromide is dissolved in 50. mL of a 0.60 M aqueous solution of potassium…

A: Here the NH4Br reacts with K2CO3 to give KBr and (NH4)2CO3 as the products. We can simply find the…

Q: How many moles of ammonia are in 500. mL of a 2.25 M aqueous ammonia solution? Find the numerical…

A: we are  required to find the number of moles of ammonia from molarity and volume

Q: A chemist prepares a solution of iron (II) bromide (FeBr₂) by measuring out 8.06 mg of FeBr₂ into a…

A: To calculate the molarity of Br- anions in the solution, we need to determine the number of moles of…

Q: Suppose 23.8 g of sodium iodide is dissolved in 350. mL of a 0.80 M aqueous solution of silver…

A:

Q: Suppose 11.1g  of lead(II) acetate is dissolved in  350.mL  of a  0.80 M  aqueous solution of…

A: Given that : The mass of lead (II) acetate = 11.1 g The volume of ammonium sulfate solution = 350 mL…

Q: A chemist prepares a solution of magnesium bromide (MgBr₂) by measuring out 45. mg of MgBr₂ into a…

A:

Q: A chemist prepares a solution of iron III  chloride    FeCl3    by measuring out  0.40g  of…

A: Given : mass of FeCl3 dissolved = 0.40 g And volume of solution prepared = 100 mL = 0.100 L…

Q: A student wants to make a 1.600 M aqueous solution of barium sulfate, BaSO4, and has a bottle…

A: To calculate the final volume of the solution for 1.6 M solution of BaSO4 containing 12.00 g of…

Q: Suppose 2.06 g of lead(II) acetate is dissolved in 250. mL of a 48.0 m M aqueous solution of…

A: Step 1:

Q: A chemist prepares a solution of vanadium III bromide VBr3 by measuring out…

A:

Q: Suppose 6.22 g of ammonium iodide is dissolved in 250. mL of a 0.20 M aqueous solution of potassium…

A: Given ,  Mass of ammonium iodide = 6.22 g Molar mass of ammonium iodide = 144.94 g/mol Moles of…

Q: Suppose 2.50 g of lead(II) acetate is dissolved in 300. mL of a 35.0 m M aqueous solution of…

A:

Q: A chemist prepares a solution of iron II bromide   FeBr2   by measuring out 17.mg of FeBr2 into a…

A:

Q: Suppose 0.428 g of ammonium sulfate is dissolved in 50. mL of a 33.0 m M aqueous solution of sodium…

A: In the given question we have to calculate the final concentration of ammonium cation in the…

Q: A chemist prepares a solution of vanadiumIII bromide VBr3 by measuring out 0.40g of VBr3 into a…

A: Molar mass of VBr3 = Atomic mass of V + 3 X Atomic mass of Br = 51 + 3 X 80 = 291 g/mol Given : Mass…

Q: A chemist prepares a solution of vanadium(III) bromide (VBr3) by measuring out 0.10 g of VBr3 into a…

A: Given: The mass of VBr3 = 0.10 g The volume of water = 100 mL We have to calculate the molarity of…

Q: 0.3120 g sample of potassium hydrogen phthalate is dissolved in 100.0 mL of water. If 25.60 mL of…

A: Weight of potassium hydrogen phthalate = 0.3120 g Volume of water = 100.0 ml = 0.100 L  (1 L =…

Q: A 0.3240 g sample of potassium hydrogen phthalate is dissolved in 100.0 mL of water. If 26.79 mL of…

A: The objective of this question is to calculate the molarity of the sodium hydroxide solution using…

Q: by measuring out  78.8mg  of  FeBr3  into a  100.mL  volumetric flask and filling to the mark…

A: Given data :  Mass of FeBr3 = 78.8 mg = 0.0788 g (1 g = 1000 mg )  Molar mass of FeBr3 = 295.6 g/mol…

Q: A 7.428 g sample of KHP, a monoprotic acid, requires 49.68 mL of a KOH solution to reach the…

A: The amount of KHP moles in the KOH , concentration:The amount of KHP moles in the sample:For the…

Q: A chemist prepares a solution of vanadiumIII bromide VBr3 by measuring out 0.50g of VBr3 into a…

A:

Q: A chemist prepares a solution of iron II  bromide    FeBr2    by measuring out  1.0g  of  FeBr2…

A: The molarity of a solution represents the number of moles of solute present in one liter of a…

Q: Suppose 20.4 g of ammonium sulfate is dissolved in 150. mL of a 0.70 M aqueous solution of sodium…

A:

Q: A chemist prepares a solution of barium acetate (Ba(CH,CO,),) by measuring out 1.3 x 10 umol of…

A:

Q: Calculate the volume in milliliters of a 10.1 M silver perchlorate solution that contains 100.g of…

A:

Q: Suppose 7.13 g of iron(II) bromide is dissolved in 100. mL of a 0.70 M aqueous solution of silver…

A: Given: Mass of iron (II) bromide i.e. FeBr2 = 7.13 g Volume of solution = 100 mL = 0.100 L…

Q: A chemist prepares a solution of potassium bromide    KBr    by measuring out  0.17g  of  KBr…

A: Given : Mass of KBr dissolved = 0.17 g Volume of final solution = 300 mL = 0.300 L…

Q: A chemist prepares a solution of potassium chloride   KCl    by measuring out  0.23g  of  KCl…

A:

Q: A student wants to make a 0.600 M aqueous solution of barium sulfate, BaSO4, and has a bottle…

A: Given Molarity = 0.600 M Mass of BaSO4 = 12 g

Q: A chemist prepares a solution of magnesium fluoride (MgF2) by measuring out 0.0553 g of magnesium…

A: Concentration in mol/L = Number of mols of solute/Volume of solution (L) Number of mols =mass/molar…

Q: A chemist prepares a solution of aluminum sulfite (Al, (SO,)) by measuring out 179. µmol of aluminum…

A:

Q: A chemist adds 490.0mL of a 0.339M silver perchlorate AgClO4 solution to a reaction flask. Calculate…

A: Given that,490.0mL of 0.339M silver per chlorate solution.