A chemist prepares a solution of sodium thiosulfate (Na, S,O,) by measuring out 121. g of sodium thiosulfate into a 200. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's sodium thiosulfate solution. Round your answer to 3 significant digits.

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### Preparation of Sodium Thiosulfate Solution

A chemist prepares a solution of sodium thiosulfate (\( \text{Na}_2\text{S}_2\text{O}_3 \)) by measuring out 121 g of sodium thiosulfate and dissolving it in a 200 mL volumetric flask. The flask is then filled to the mark with water to ensure the correct volume of the solution.

### Problem

Calculate the concentration of sodium thiosulfate in the solution in moles per liter (mol/L). Provide your answer rounded to 3 significant digits.

#### Solution Steps:

1. **Determine the Molar Mass of Sodium Thiosulfate:**

   \[
   \text{Molar mass of } \text{Na}_2\text{S}_2\text{O}_3 = 2(22.99 \text{ g/mol}) + 2(32.07 \text{ g/mol}) + 3(16.00 \text{ g/mol})
   \]
   \[
   = 2(22.99) + 2(32.07) + 3(16.00)
   \]
   \[
   = 45.98 + 64.14 + 48.00
   \]
   \[
   \approx 158.12 \text{ g/mol}
   \]

2. **Convert Mass to Moles:**

   \[
   \text{Moles of } \text{Na}_2\text{S}_2\text{O}_3 = \frac{\text{Mass}}{\text{Molar mass}} = \frac{121 \text{ g}}{158.12 \text{ g/mol}}
   \]
   \[
   \approx 0.765 \text{ moles}
   \]

3. **Convert Volume to Liters:**

   \[
   \text{Volume} = 200 \text{ mL} = 0.200 \text{ L}
   \]

4. **Calculate the Concentration:**

   \[
   \text{Concentration} = \frac{\text{Moles}}{\text{Volume}} = \frac{0.765 \text{ moles}}{0.200 \text{ L}}
   \]
   \[
   \approx 3.825 \text{ mol/L}
Transcribed Image Text:### Preparation of Sodium Thiosulfate Solution A chemist prepares a solution of sodium thiosulfate (\( \text{Na}_2\text{S}_2\text{O}_3 \)) by measuring out 121 g of sodium thiosulfate and dissolving it in a 200 mL volumetric flask. The flask is then filled to the mark with water to ensure the correct volume of the solution. ### Problem Calculate the concentration of sodium thiosulfate in the solution in moles per liter (mol/L). Provide your answer rounded to 3 significant digits. #### Solution Steps: 1. **Determine the Molar Mass of Sodium Thiosulfate:** \[ \text{Molar mass of } \text{Na}_2\text{S}_2\text{O}_3 = 2(22.99 \text{ g/mol}) + 2(32.07 \text{ g/mol}) + 3(16.00 \text{ g/mol}) \] \[ = 2(22.99) + 2(32.07) + 3(16.00) \] \[ = 45.98 + 64.14 + 48.00 \] \[ \approx 158.12 \text{ g/mol} \] 2. **Convert Mass to Moles:** \[ \text{Moles of } \text{Na}_2\text{S}_2\text{O}_3 = \frac{\text{Mass}}{\text{Molar mass}} = \frac{121 \text{ g}}{158.12 \text{ g/mol}} \] \[ \approx 0.765 \text{ moles} \] 3. **Convert Volume to Liters:** \[ \text{Volume} = 200 \text{ mL} = 0.200 \text{ L} \] 4. **Calculate the Concentration:** \[ \text{Concentration} = \frac{\text{Moles}}{\text{Volume}} = \frac{0.765 \text{ moles}}{0.200 \text{ L}} \] \[ \approx 3.825 \text{ mol/L}
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