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A chemist prepares a solution of sodium chloride (NaC1) by weighing out 7.20 g of sodium chloride into a 50. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/dL of the chemist's sodium chloride solution. Be sure your answer has the correct number of significant digits.

A chemist prepares a solution of sodium chloride (NaC1) by weighing out 7.20 g of sodium chloride into a 50. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/dL of the chemist's sodium chloride solution. Be sure your answer has the correct number of significant digits.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Please put the right number of significant figures

**Sodium Chloride Solution Concentration Calculation** A chemist prepares a solution of sodium chloride (NaCl) by weighing out 7.20 g of sodium chloride into a 50.0 mL volumetric flask and filling the flask to the mark with water. *Calculate the concentration in g/dL of the chemist's sodium chloride solution. Be sure your answer has the correct number of significant digits.* **Solution Representation & Tools:** - **Units Box**: Shows the unit `g/dL`. - **Answer Box**: Used to input your calculated value. - **Buttons**: - `x`: Cancel or clear input. - `⟲ (Reload)`: Reset the calculation or input. - `?`: Help or additional information. **Steps to Solve:** 1. **Convert the Volume from mL to dL:** - 50.0 mL = 50.0/100 = 0.500 dL 2. **Calculate the Concentration:** - \( \text{Concentration} = \frac{\text{Mass of NaCl}}{\text{Volume in dL}} \) - \( \text{Concentration} = \frac{7.20 \, \text{g}}{0.500 \, \text{dL}} = 14.4 \, \text{g/dL} \) Therefore, the concentration of the sodium chloride solution is \( 14.4 \, \text{g/dL} \). **Note:** Make sure the number of significant digits in your answer matches the data provided in the problem. Here, both the mass (7.20 g) and the volume (50.0 mL) are given to three significant digits, leading to a concentration value also given to three significant digits.
Transcribed Image Text:**Sodium Chloride Solution Concentration Calculation** A chemist prepares a solution of sodium chloride (NaCl) by weighing out 7.20 g of sodium chloride into a 50.0 mL volumetric flask and filling the flask to the mark with water. *Calculate the concentration in g/dL of the chemist's sodium chloride solution. Be sure your answer has the correct number of significant digits.* **Solution Representation & Tools:** - **Units Box**: Shows the unit `g/dL`. - **Answer Box**: Used to input your calculated value. - **Buttons**: - `x`: Cancel or clear input. - `⟲ (Reload)`: Reset the calculation or input. - `?`: Help or additional information. **Steps to Solve:** 1. **Convert the Volume from mL to dL:** - 50.0 mL = 50.0/100 = 0.500 dL 2. **Calculate the Concentration:** - \( \text{Concentration} = \frac{\text{Mass of NaCl}}{\text{Volume in dL}} \) - \( \text{Concentration} = \frac{7.20 \, \text{g}}{0.500 \, \text{dL}} = 14.4 \, \text{g/dL} \) Therefore, the concentration of the sodium chloride solution is \( 14.4 \, \text{g/dL} \). **Note:** Make sure the number of significant digits in your answer matches the data provided in the problem. Here, both the mass (7.20 g) and the volume (50.0 mL) are given to three significant digits, leading to a concentration value also given to three significant digits.
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