A chemist prepares a solution of silver(I) nitrate (AGNO,) by measuring out 107. µmol of silver(1) nitrate into a 150. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mmol/L of the chemist's silver(I) nitrate solution. Be sure your answer has the correct number of significant digits. mmol

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Chapter6: Types Of Chemical Reactions And Solution Stoichiometry
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please put the right number of significant figures

**Transcription:**

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A chemist prepares a solution of silver(I) nitrate (AgNO₃) by measuring out 107. μmol of silver(I) nitrate into a 150. mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mmol/L of the chemist's silver(I) nitrate solution. Be sure your answer has the correct number of significant digits.

[Diagram]

1. A box labeled "mmol/L" is shown.
2. There are three buttons below the text box: 
   - An 'X' button for clearing input.
   - A '↻' button probably used for resetting.
   - A '?' button likely providing help or hints.

---

**Explanation:**

1. **Converting µmol to mmol:**
   - Given: 107. µmol = 0.107 mmol

2. **Volume conversion:**
   - Given: 150. mL = 0.150 L 

3. **Calculating concentration (C):**
   \[
   C = \frac{\text{Number of moles (mmol)}}{\text{Volume (L)}}
   \]
   \[
   C = \frac{0.107 \text{ mmol}}{0.150 \text{ L}} = 0.713 \text{ mmol/L}
   \]

The concentration of the chemist's silver(I) nitrate solution is **0.713 mmol/L**.
Transcribed Image Text:**Transcription:** --- A chemist prepares a solution of silver(I) nitrate (AgNO₃) by measuring out 107. μmol of silver(I) nitrate into a 150. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mmol/L of the chemist's silver(I) nitrate solution. Be sure your answer has the correct number of significant digits. [Diagram] 1. A box labeled "mmol/L" is shown. 2. There are three buttons below the text box: - An 'X' button for clearing input. - A '↻' button probably used for resetting. - A '?' button likely providing help or hints. --- **Explanation:** 1. **Converting µmol to mmol:** - Given: 107. µmol = 0.107 mmol 2. **Volume conversion:** - Given: 150. mL = 0.150 L 3. **Calculating concentration (C):** \[ C = \frac{\text{Number of moles (mmol)}}{\text{Volume (L)}} \] \[ C = \frac{0.107 \text{ mmol}}{0.150 \text{ L}} = 0.713 \text{ mmol/L} \] The concentration of the chemist's silver(I) nitrate solution is **0.713 mmol/L**.
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