A chemist prepares a solution of copper(II) sulfate (CuSO,) by weighing out 30.0 g of copper(II) sulfate into a 300. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/L of the chemist's copper(II) sulfate solution. Be sure your answer has the correct number of significant digits. ?

Chemistry
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Chapter1: Chemical Foundations
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A chemist prepares a solution of copper(II) sulfate (\( \text{CuSO}_4 \)) by weighing out 30.0 g of copper(II) sulfate into a 300. mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in g/L of the chemist's copper(II) sulfate solution. Be sure your answer has the correct number of significant digits.

There is a text input box for entering the result of the calculation. It is accompanied by a unit label “g/L”.

To calculate the concentration:
1. Convert the volume from mL to L: 300 mL = 0.300 L.
2. Use the formula for concentration: 
   \[
   \text{Concentration (g/L)} = \frac{\text{Mass of solute (g)}}{\text{Volume of solution (L)}} 
   \]
3. Substitute the values:
   \[
   \text{Concentration} = \frac{30.0 \, \text{g}}{0.300 \, \text{L}} = 100 \, \text{g/L}
   \]

Ensure the final answer is provided with three significant figures, reflecting the precision of the initial data provided in the problem.
Transcribed Image Text:A chemist prepares a solution of copper(II) sulfate (\( \text{CuSO}_4 \)) by weighing out 30.0 g of copper(II) sulfate into a 300. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/L of the chemist's copper(II) sulfate solution. Be sure your answer has the correct number of significant digits. There is a text input box for entering the result of the calculation. It is accompanied by a unit label “g/L”. To calculate the concentration: 1. Convert the volume from mL to L: 300 mL = 0.300 L. 2. Use the formula for concentration: \[ \text{Concentration (g/L)} = \frac{\text{Mass of solute (g)}}{\text{Volume of solution (L)}} \] 3. Substitute the values: \[ \text{Concentration} = \frac{30.0 \, \text{g}}{0.300 \, \text{L}} = 100 \, \text{g/L} \] Ensure the final answer is provided with three significant figures, reflecting the precision of the initial data provided in the problem.
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