A chemist must prepare 925. mL of 435. mM aqueous aluminum sulfate (Al₂(SO4)3) working solution. She'll do this by pouring out some 0.596 L mol aqueous aluminum sulfate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the aluminum sulfate stock solution that the chemist should pour out. Round your answer to 3 significant digits. 0mL 0 00 x S ? Check Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility DII DD 3) F2 FB F9 F10 F12 esc Explanation Ő ! 1 F1 2 #3 80 F3 DS 4 F4 % 5 MacBook Air St A 6 F6 & 7 aa F7 * 00 8 ( 9 ) 0 F11 +

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**Transcription for Educational Website**

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**Chemistry Problem: Preparation of a Dilute Aqueous Aluminum Sulfate Solution**

*A chemist must prepare 925 mL of 0.435 mM aqueous aluminum sulfate (Al2(SO4)3) working solution. She'll do this by pouring out some 1.39 M aqueous aluminum sulfate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the aluminum sulfate stock solution that the chemist should pour out. Round your answer to 3 significant digits.*

**Input Box Field:**
- Volume (mL): [Input Box]

**Options:**
- [Check] [Explanation]

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**Explanation of Diagram:**

The image does not contain any graphs or diagrams but includes a simple box for volume input. Here’s a detailed explanation of the process involved in solving the problem:

1. **Understanding the Given Data:**
   - Final Volume (\(V_2\)): 925 mL
   - Final Concentration (\(C_2\)): 0.435 mM (millimolar)
   - Stock Solution Concentration (\(C_1\)): 1.39 M (molar, which equals 1390 mM)

2. **Formula Used:**
   To find the volume of the stock solution (\(V_1\)), the dilution formula \(C_1V_1 = C_2V_2\) is used.
   
3. **Calculation Process:**
   - Rearrange to find \(V_1\): \( V_1 = \dfrac{C_2 \times V_2}{C_1}\)
   - Plug in the values: 
     \( V_1 = \dfrac{0.435 \times 925}{1390} \)
   - Perform the calculation and round to 3 significant digits.

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**Note:** Please enter your calculated volume in the input box provided and click 'Check' to validate your answer.

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**Footer:** 

- © 2022 McGraw Hill LLC. All Rights Reserved.
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Transcribed Image Text:**Transcription for Educational Website** --- **Chemistry Problem: Preparation of a Dilute Aqueous Aluminum Sulfate Solution** *A chemist must prepare 925 mL of 0.435 mM aqueous aluminum sulfate (Al2(SO4)3) working solution. She'll do this by pouring out some 1.39 M aqueous aluminum sulfate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the aluminum sulfate stock solution that the chemist should pour out. Round your answer to 3 significant digits.* **Input Box Field:** - Volume (mL): [Input Box] **Options:** - [Check] [Explanation] --- **Explanation of Diagram:** The image does not contain any graphs or diagrams but includes a simple box for volume input. Here’s a detailed explanation of the process involved in solving the problem: 1. **Understanding the Given Data:** - Final Volume (\(V_2\)): 925 mL - Final Concentration (\(C_2\)): 0.435 mM (millimolar) - Stock Solution Concentration (\(C_1\)): 1.39 M (molar, which equals 1390 mM) 2. **Formula Used:** To find the volume of the stock solution (\(V_1\)), the dilution formula \(C_1V_1 = C_2V_2\) is used. 3. **Calculation Process:** - Rearrange to find \(V_1\): \( V_1 = \dfrac{C_2 \times V_2}{C_1}\) - Plug in the values: \( V_1 = \dfrac{0.435 \times 925}{1390} \) - Perform the calculation and round to 3 significant digits. --- **Note:** Please enter your calculated volume in the input box provided and click 'Check' to validate your answer. --- **Footer:** - © 2022 McGraw Hill LLC. All Rights Reserved. - Terms of Use | Privacy Center | Accessibility
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