A chemist must prepare 925. mL of 435. mM aqueous aluminum sulfate (Al₂(SO4)3) working solution. She'll do this by pouring out some 0.596 L mol aqueous aluminum sulfate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the aluminum sulfate stock solution that the chemist should pour out. Round your answer to 3 significant digits. 0mL 0 00 x S ? Check Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility DII DD 3) F2 FB F9 F10 F12 esc Explanation Ő ! 1 F1 2 #3 80 F3 DS 4 F4 % 5 MacBook Air St A 6 F6 & 7 aa F7 * 00 8 ( 9 ) 0 F11 +
A chemist must prepare 925. mL of 435. mM aqueous aluminum sulfate (Al₂(SO4)3) working solution. She'll do this by pouring out some 0.596 L mol aqueous aluminum sulfate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the aluminum sulfate stock solution that the chemist should pour out. Round your answer to 3 significant digits. 0mL 0 00 x S ? Check Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility DII DD 3) F2 FB F9 F10 F12 esc Explanation Ő ! 1 F1 2 #3 80 F3 DS 4 F4 % 5 MacBook Air St A 6 F6 & 7 aa F7 * 00 8 ( 9 ) 0 F11 +
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Transcription for Educational Website**
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**Chemistry Problem: Preparation of a Dilute Aqueous Aluminum Sulfate Solution**
*A chemist must prepare 925 mL of 0.435 mM aqueous aluminum sulfate (Al2(SO4)3) working solution. She'll do this by pouring out some 1.39 M aqueous aluminum sulfate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the aluminum sulfate stock solution that the chemist should pour out. Round your answer to 3 significant digits.*
**Input Box Field:**
- Volume (mL): [Input Box]
**Options:**
- [Check] [Explanation]
---
**Explanation of Diagram:**
The image does not contain any graphs or diagrams but includes a simple box for volume input. Here’s a detailed explanation of the process involved in solving the problem:
1. **Understanding the Given Data:**
- Final Volume (\(V_2\)): 925 mL
- Final Concentration (\(C_2\)): 0.435 mM (millimolar)
- Stock Solution Concentration (\(C_1\)): 1.39 M (molar, which equals 1390 mM)
2. **Formula Used:**
To find the volume of the stock solution (\(V_1\)), the dilution formula \(C_1V_1 = C_2V_2\) is used.
3. **Calculation Process:**
- Rearrange to find \(V_1\): \( V_1 = \dfrac{C_2 \times V_2}{C_1}\)
- Plug in the values:
\( V_1 = \dfrac{0.435 \times 925}{1390} \)
- Perform the calculation and round to 3 significant digits.
---
**Note:** Please enter your calculated volume in the input box provided and click 'Check' to validate your answer.
---
**Footer:**
- © 2022 McGraw Hill LLC. All Rights Reserved.
- Terms of Use | Privacy Center | Accessibility](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F621954ed-ec20-4c07-b25b-e8811e0f0e49%2F31022602-bd94-4aa8-983b-eedcd01e9315%2Fsco1x2k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website**
---
**Chemistry Problem: Preparation of a Dilute Aqueous Aluminum Sulfate Solution**
*A chemist must prepare 925 mL of 0.435 mM aqueous aluminum sulfate (Al2(SO4)3) working solution. She'll do this by pouring out some 1.39 M aqueous aluminum sulfate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the aluminum sulfate stock solution that the chemist should pour out. Round your answer to 3 significant digits.*
**Input Box Field:**
- Volume (mL): [Input Box]
**Options:**
- [Check] [Explanation]
---
**Explanation of Diagram:**
The image does not contain any graphs or diagrams but includes a simple box for volume input. Here’s a detailed explanation of the process involved in solving the problem:
1. **Understanding the Given Data:**
- Final Volume (\(V_2\)): 925 mL
- Final Concentration (\(C_2\)): 0.435 mM (millimolar)
- Stock Solution Concentration (\(C_1\)): 1.39 M (molar, which equals 1390 mM)
2. **Formula Used:**
To find the volume of the stock solution (\(V_1\)), the dilution formula \(C_1V_1 = C_2V_2\) is used.
3. **Calculation Process:**
- Rearrange to find \(V_1\): \( V_1 = \dfrac{C_2 \times V_2}{C_1}\)
- Plug in the values:
\( V_1 = \dfrac{0.435 \times 925}{1390} \)
- Perform the calculation and round to 3 significant digits.
---
**Note:** Please enter your calculated volume in the input box provided and click 'Check' to validate your answer.
---
**Footer:**
- © 2022 McGraw Hill LLC. All Rights Reserved.
- Terms of Use | Privacy Center | Accessibility
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