A chemist has three different acid solutions. The first acid solution contains 20 % acid, the second contains 40 % and the third contains 80 % . He wants to use all three solutions to obtain a mixture of 60 liters containing 60 % acid, using 3 times as much of the 80 % solution as the 40 % solution. How many liters of each solution should be used? The chemist should use liters of 20 % solution, liters of 40 % solution, and liters of 80 % solution.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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A chemist has three different acid solutions. The first acid solution contains 20 % acid, the second
contains 40 % and the third contains 80 % . He wants to use all three solutions to obtain a mixture
of 60 liters containing 60 % acid, using 3 times as much of the 80 % solution as the 40 % solution.
How many liters of each solution should be used?
The chemist should use
liters of 20 % solution,
liters of 40 % solution,
and
liters of 80 % solution.
esc
Search or type UF
1
2
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6
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E
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# 3
Transcribed Image Text:A chemist has three different acid solutions. The first acid solution contains 20 % acid, the second contains 40 % and the third contains 80 % . He wants to use all three solutions to obtain a mixture of 60 liters containing 60 % acid, using 3 times as much of the 80 % solution as the 40 % solution. How many liters of each solution should be used? The chemist should use liters of 20 % solution, liters of 40 % solution, and liters of 80 % solution. esc Search or type UF 1 2 4 6 Q W E R T LO # 3
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