A chemist believes that corn fields must be treated with a fertilizer on average 6 times over the course of the growing season in order to maintain optimal plant growth. However, she is curious aboutwhether the corn could do equally as well with fewer treatments.The null hypothesis would be Ho: μ = 6.The alternative hypothesis would be Ha: < 6.What would a Type I error be in this situation?We would say that 6 treatments work when we really need fewer.We would say that fewer treatments work when we really need 6.We would say 6 treatments work when we really need more.We would say that more treatments are needed when we need fewer.

Approach to solving the question:In hypothesis testing, a Type I error occurs when we reject a true…

Answered: A chemist believes that corn fields…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Kenya is a behavioral psychologist who works with children on the Autism Spectrum. She suggests that blowing bubbles may effect children's eye contact (she hasn't predicted if it would increase or decrease). She works with a student who makes 5 points of eye contact in a session. How would the NULL hypothesis be state for her study using bubbles? µ < 5 µ = 5 µ > 5 µ ≠ 5
In 2022, the CDC reported that 12.5% of U.S. adults currently smoke cigarettes. From the same report, a random sample of 12,405 Ohioans was taken with 2543 being current smokers. Using α = 0.05, test whether the proportion of Ohioans that smoke cigarettes is different than the proportion of U.S. adults
The largest cat in North America is the Jaguar, they can sometimes be seen in the mountains of southern Texas, Arizona and New Mexico, (and less recently southern California). The rate of observances by humans is about 3/20 years. Assume we don't get Trump's border wall which would isolate the US population from the rest, and presumably cut off their chance of breeding. Chances of seeing 5 or more separate Jaguars within 5 years is 0.0011. a. Your cameras also produce pictures of wolf sized canids, either wolves or coy-wolves in the same region (very different times). Each year your cameras catch about 40 of these animals and about 30 cougars and about 400 bear and 800 feral Hogs. Assume that these numbers are all population rates for poisson. Given your camera Network catches a non human large animal (and the above list is all of them): What is the probability it is a jaguar? What is the probability it is a feral hog? Out of 15 large non-human animals, what is the probability…
Simone read online that the failure rate in Arizona for the first attempt of the written driver’s test is 60%. Simone thinks the Arizona rate is less than 60%. To investigate, she selects an SRS of 50 Arizona drivers and finds that 27 failed their first written driving test. To determine if this provides convincing evidence that the failure rate for Arizona is less than 60%, 200 trials of a simulation are conducted. Simone’s hypotheses are: H0: p = 60% and Ha: p < 60%, where p = the true proportion of Arizona drivers who fail the first attempt of the written driver’s test. Based on the results of the simulation, the estimated P-value of this test is 0.035. Using a = 0.01, what conclusion should Simone reach? A) Because the P-value of 0.035 > a, Simone should reject H0. There is convincing evidence that the Arizona written driver’s test has a true first-attempt failure rate less than 60%. B) Because the P-value of 0.035 > a, Simone should reject H0. There is not convincing…
A hairdresser wanted to see if her clients bought more products at the end of their appointment if they were given lots of compliments. She decided to test this theory using an experiment. She randomly assigned 24 clients to receive either zero compliments, 5 compliments, or 10 compliments during their appointment. She recorded how many products they purchased after their appointment as her DV. She firstly hypothesised that no-compliment clients (M = 0.38) would purchase fewer products than clients who received 5 compliments (M = 1.50). She secondly hypothesised that 5-compliment clients would purchase fewer products than 10-compliment clients (M = 3.63). Thus, she conducted two comparisons. The initial ANOVA was significant. Using an alpha of .05, results for the follow-up tests confirmed her first hypothesis, with an obtained t value of 2.60, but did not confirm her second hypothesis, with an obtained t value of 1.20. She later realised that she did not use a Bonferroni-corrected…
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A research center claims that 31% of adults in a certain country would travel into space on a commercial flight if they could afford it. In a random sample of 800 adults in that country, 33% say that they would travel into space on a commercial flight if they could afford it. At a =0.01, is there enough evidence to reject the research center's claim? Complete parts (a) through (d) below. C No more than % of adults in the country would travel into space on a commercial ight it they could attord it. Let p be the population proportion of successes, where a success is an adult in the country who would travel into space on a commercial flight if they could afford it. State Ho and H Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.) OA Ho: ps OB. Ho: p> OC. Ho: p H p= Ha:p> H ps VE Ho: p= 0.31 O D. Ho: p< OF H: p2 H: p2 H p 0.31 (b) Use technology to find the P-value. Identify the standardized test statistic. z= 1.22…
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